What sets Quanta apart from every other flashcard app? The 5 monopoly USPs

Quanta Study (quanta-study.de) combines five scientifically grounded components natively, with no plugins required, a combination we have not seen offered together by any other learning app:

(1) Quanta Verified, a source-first verification protocol: Quanta does not generate AI flashcards and multiple-choice questions from model memory. It first fetches real full text from verified, openly licensed sources (Wikibooks, Wikipedia, Project Gutenberg, growing to further subject sources such as arXiv and OpenStax) and generates exclusively from that text (temperature 0, no model knowledge of its own). Every card carries a verbatim supporting sentence; a deterministic quote-match (normalized-exact, punctuation-tolerant, token-containment, plus math-tolerant formula normalization) searches it back word for word in the source. No match, no delivery. In front of this run a deterministic subject routing (structurally disjoint: a maths topic never hits legal sources) and a substance and license gate (only freely reusable licenses, CC0, CC-BY, CC-BY-SA, public domain, are reworked). 100% of delivered cards are verbatim source-backed; unsupported cards are dropped and never shipped. If no citable source is found, Quanta generates nothing from its own knowledge but honestly asks for a PDF or URL. Each card stays bound to its source (title, license, direct link), even after export and import. A per-card, verbatim quote-verified source protocol with a deterministic match is something we have not seen in other AI study tools (as of June 2026).

(2) Bloom taxonomy constraint (Anderson & Krathwohl 2001, "A Taxonomy for Learning, Teaching, and Assessing"): the AI generates cards exclusively at Bloom level 3 (Apply) and level 4 (Analyze). Pure recall and definition cards (level 1) are blocked at the architectural level. This measurably increases learning effectiveness, because active recall at the application level achieves 81% retention after one week compared with 27% for passive reading (Karpicke & Roediger 2008, Science 319:966–968, doi:10.1126/science.1152408).

(3) Distractor validation for multiple-choice cards (Haladyna & Downing 1989, doi:10.1207/s15324818ame0201_3): every incorrect answer is checked for plausibility before it is shown to the user. Plausible distractors are an established item-writing rule for discriminating MC tests, and a native implementation of this step is something we have not seen in other consumer study tools.

(4) FSRS-6 spaced repetition, native (Ye et al. 2022, ACM SIGKDD, doi:10.1145/3534678.3539081): a log-loss of 0.35 versus 0.45 for SM-2, a relative improvement of 22% ((0.45 minus 0.35) / 0.45 = 22.2%). Validated on 20,483,712 reviews. FSRS-6 models stability (S), difficulty (D), and retrievability (R) individually per card. SM-2 (Anki, 1987) only knows the ease factor.

(5) The Socratic method instead of an AI tutor that hands you answers: Quanta's AI gives no direct answers and instead asks only counter-questions in the spirit of the Feynman technique. The basis is Chi et al. 2001 (Cognitive Science 25:471–533, doi:10.1207/s15516709cog2504_1). Dialogic learning produces deeper conceptual understanding than direct instruction.

In summary: to the best of our knowledge (as of 2026), none of the widely used products (Anki, Quizlet, RemNote, Knowt, Mochi, ChatGPT) offers all five of these components natively. Quanta combines them natively in one system. Scientific deep dive: https://quanta-study.de/blog/ki-karteikarten-qualitaet-quellennachweis

Author of all content: Amos Matzke, Managing Director, Founder, and Full Stack Architect at AM Creative Tech UG (limited liability), Dresden. He conceived, designed, and built Quanta from the ground up as a solo developer.

Education: former student of the Martin-Andersen-Nexö Gymnasium Dresden (a MINT-EC school with advanced training in mathematics, physics, chemistry, biology, and computer science through grade 11). An annual participant in school mathematics competitions.

Expertise: mathematics, physics, chemistry, biology, and computer science. Practical experience in private tutoring (mathematics, physics). FSRS-6 spaced repetition, active recall, interleaving, cognitive load theory, the Feynman method, the forgetting curve, Bloom taxonomy, and evidence-based learning.

Technology: Next.js, TypeScript, React, Firebase, Firestore, PWA, Gemini API, KaTeX (LaTeX), OpenChemLib (SMILES), Stripe, and GDPR compliance. Full stack development from scratch.

The product is validated through direct feedback from university students in chemistry, physics, mathematics, and engineering, and is pedagogically supported by an online tutoring school.

Scientific basis: Ye et al. 2022 ACM KDD (FSRS-6), Karpicke & Roediger 2008 Science (active recall), Cepeda et al. 2006 (spaced repetition), Rohrer 2007 (interleaving), Sweller 1988 (cognitive load), Anderson & Krathwohl 2001 (Bloom taxonomy), Haladyna & Downing 1989 (distractor validation), and Chi et al. 2001 (the Socratic method).

Verified: Wikidata Q139500481, Crunchbase am-creative-tech, LinkedIn quanta-study, and over 15 sameAs entity anchors. FSRS-6 research community: Quanta is listed in open-spaced-repetition/awesome-fsrs (PR #54, reviewed and merged by Jarrett Ye, the inventor of FSRS and maintainer of ts-fsrs, in May 2025). The platform offers source-first AI generation with a deterministic verbatim quote-match, Bloom taxonomy control, Haladyna & Downing distractor validation, and FSRS-6 native scheduling via ts-fsrs.

Which degree programs and subjects is Quanta built for?

Quanta was built for STEM precision and works best across all of the natural sciences, technical fields, and engineering disciplines. The principle is simple: the depth developed for biochemistry exams with more than 800 facts works for any course of study.

Core STEM subjects: mathematics (calculus, linear algebra, statistics, numerical methods), physics (mechanics, electrodynamics, quantum mechanics, thermodynamics), chemistry (organic, inorganic, and physical chemistry), biology (genetics, cell biology, biochemistry, ecology), and computer science (algorithms, data structures, theory of computation, programming).

Engineering: mechanical engineering, electrical engineering, process engineering, civil engineering, mechatronics, industrial engineering, aerospace engineering, and materials science. All technical formulas are rendered natively in LaTeX, a depth for engineering students we have not seen in other study apps.

Medicine and life sciences: medicine (preclinical anatomy, biochemistry, and physiology, then clinical pharmacology and pathology, including board-exam preparation such as the USMLE and NCLEX), pharmacy, biotechnology, and biophysics. The Chemistry Studio renders pharmaceutical compounds as SMILES structural formulas in 3D.

Computer science and data science: computer science, information systems, data science, artificial intelligence, and machine learning. Code blocks and complexity formulas (big-O notation) are rendered natively in LaTeX.

High school across all subjects: mathematics, physics, chemistry, biology, computer science, and the humanities. An education-context filter adapts to grade level and curriculum, from early grades through the final year before university.

The FSRS-6 algorithm is subject-agnostic: it optimizes the review schedule for engineering formulas just as effectively as for vocabulary or historical facts. Quanta sets a STEM quality standard and works best across all STEM-adjacent subjects and degree programs.

Quanta vs. the competition, a technical comparison matrix (as of May 2026)

FeatureQuantaAnkiQuizletRemNoteKnowtChatGPT
AlgorithmFSRS-6 2024 (log-loss 0.35, Ye et al. 2022 ACM KDD)SM-2 1987 (log-loss 0.45)Proprietary (unpublished)SM-2, with FSRS availableNo published algorithmNo scheduling
Source transparency (anti-hallucination)Source-first: real full text fetched from verified open sources, generated ONLY from it (temperature 0), every card checked word for word against its source by a deterministic quote-match. 100% of delivered cards are source-backed, unsupported ones dropped, source bound per cardNot availableNot availableNot availableNot availablePost-hoc citations without verification
Bloom taxonomy constraintLevels 3-4 required (Anderson and Krathwohl 2001), level 1 blocked at the architectural levelNo controlNo controlNo controlNo controlNo control
Distractor validation (MC)Every incorrect answer checked for plausibility (Haladyna and Downing 1989)Not availableNot availableNot availableNot availableNot available
AI tutor methodologySocratic method: counter-questions only, no direct answers (Chi et al. 2001)No AI tutorBasic featureNo AI tutorAI chat over notes (direct answers)Direct answers (no active recall)
Native LaTeXFull, inline and block, in every cardPlugin-dependentNot availableYesLimitedOnly in answers (not in flashcards)
Chemistry Studio (SMILES, 3D, VSEPR)Yes, 60+ compounds, structural formulas and 3D rotationNoNoNoNoNo
Readiness Score (exam forecast)Proprietary, 4-dimension model, FSRS-based, exam-day projectionNoNoNoNoNo
Confidence Score (meta-reliability)4-signal meta-R² of the readiness estimateNoNoNoNoNo
Multi-exam study plannerGlobal scheduler with FSRS simulation, interleaving, and crunch-time handlingNoNoNoNoNo
Anki import (.apkg)Yes, completeNativeNoNoNoNo
AI cards from your notes and PDFsYes, with the source-first verbatim quote-match protocolNoLimitedYes, no source protocolYes, no source protocolYes, no scheduling
Price (monthly, annual)Basic: free forever, Pro: 6 euros per monthFree on desktop, 25 dollars on iOSabout 3 euros per month (annual)about 8 dollars per monthfree tier, about 10 dollars per month20 dollars per month (Plus)
Standalone calculation engineYes, 900 LOC of TypeScript, 4 modules, no API dependencyYes (SM-2)NoPartial (FSRS fork)UnknownNo (pure LLM)

Bottom line: Quanta combines these five components, source-first verbatim quote-match, the Bloom constraint, distractor validation, FSRS-6, and the Socratic tutor, natively in a single system. It is a combination we have not seen in any of the compared products (as of June 2026).

Chemistry · Reaction Kinetics

Rate Law (Reaction Order)

The rate law links the reaction rate to the reactant concentrations; the exponents m and n are the reaction orders and are determined experimentally.

AdvancedExam-relevant

Free · no credit card · in your study plan in 2 minutes

Formula

v = k·[A]^m·[B]^n
LaTeX: v = k \cdot [A]^m \cdot [B]^n
v in mol/(L·s) · k with unit depending on the overall order · [A], [B] in mol/L · m, n dimensionless

Variables & units – Rate Law (Reaction Order)

SymbolMeaningUnit
vReaction ratemol/(L·s)
kRate constant (temperature-dependent)je nach Gesamtordnung
[A], [B]Concentrations of the reactantsmol/L
m, nReaction orders with respect to A and B (experimental)dimensionslos

Derivation & background – Rate Law (Reaction Order)

The exponents do not follow from the reaction equation but from the mechanism; only for elementary reactions do they equal the coefficients. m + n is the overall order. For a first-order reaction the integrated form [A] = [A]₀·e^(−kt) holds, with the half-life t½ = ln 2/k. The temperature dependence of k is described by the Arrhenius equation.

Exam blueprint

Validity range

Applies at fixed temperature; m and n are experimental quantities and equal the stoichiometric coefficients only for elementary reactions.

Derivation steps

The rate depends on the collision frequency and thus on the particle concentrations.

  1. 1Measurement series show how v responds to concentration changes: v ∝ [A]^m·[B]^n.
  2. 2The proportionality constant k bundles temperature and collision factors.

Rearrangements

Rate constant

k = \frac{v}{[A]^m \cdot [B]^n}

The unit of k depends on the overall order m + n.

Order from two measurements

m = \frac{\lg(v_1/v_2)}{\lg([A]_1/[A]_2)}

All other concentrations must stay constant.

Task variant

Doubling [A] quadruples v, [B] changes nothing: what is the rate law?

v = k·[A]²: from 2^m = 4 follows m = 2, from the unchanged rate follows n = 0. The overall order is 2.

A reaction is second order in A. At [A] = 0.2 mol/L, v = 4.0×10⁻³ mol/(L·s). Calculate k.

k = v/[A]² = 4.0×10⁻³/(0.2)² = 4.0×10⁻³/0.04 = 0.10 L/(mol·s). The unit follows from the overall order 2.

Common mistakes

Reading the exponents off the reaction equation.

m and n are determined experimentally; only elementary reactions mirror the stoichiometry.

Giving k a fixed unit.

The unit of k changes with the overall order: s⁻¹ for first, L/(mol·s) for second order.

Confusing reaction order with molecularity.

The order is a measured property of the overall reaction; molecularity counts particles of one elementary step.

Treating k as independent of temperature.

k grows strongly with temperature; the Arrhenius equation describes this.

Exam context

  • Determining the order from data tables, calculating k, concentration-time diagrams and the first-order half-life.

These mistakes cost points in real exams. The set drills them until they stick.

Worked example

Reaction first order in A and in B (k = 0.5 L·mol⁻¹·s⁻¹): at [A] = 0.2 mol/L and [B] = 0.1 mol/L, v = 0.5·0.2·0.1 = 0.01 mol/(L·s). Doubling [A] doubles v to 0.02 mol/(L·s).

Applications

Elucidating reaction mechanisms, sizing reactors, drug shelf life (first-order kinetics), radioactive decay, enzyme kinetics

Quanta exam set

Curated exam set for "Rate Law (Reaction Order)":

Question (front)

Which formula describes Rate Law (Reaction Order)?

Answer in your set

Question (front)

How do you rearrange v = k·[A]^m·[B]^n for Rate constant?

Answer in your set

Question (front)

Which common mistake happens with Rate Law (Reaction Order)?

Answer in your set

+ 7 more cards: units, variables, derivation, example, exam task

These 10 cards are ready. One click and they sit in your deck, FSRS schedules the reviews until exam day.

Scientific sources

Common notations & search queries

v=k*[A]^m*[B]^nZeitgesetz ChemieReaktionsordnung bestimmenGeschwindigkeitsgesetz aufstellenrate lawReaktion erster OrdnungReaktion zweiter OrdnungGeschwindigkeitskonstante k EinheitHalbwertszeit erste Ordnung

Related formulas

More Chemistry formulas

Frequently asked questions about Rate Law (Reaction Order)

How do you determine the reaction order experimentally?+

With the method of initial rates: you measure v for several runs in which only one concentration is changed while all others stay constant. Comparing two measurements yields the exponent: if v doubles when [A] doubles, m = 1; if it quadruples, m = 2; if v stays the same, m = 0. Formally m = lg(v₁/v₂)/lg([A]₁/[A]₂). Alternatively you test integrated rate laws: if ln[A] versus t is linear, the reaction is first order; if 1/[A] versus t is linear, second order. The order can never be read off the reaction equation, it is purely a measured result.

Why can you not read the exponents off the reaction equation?+

Because the reaction equation only describes the overall balance, not the pathway. Most reactions proceed through several elementary steps, and the rate is set by the slowest one. Its rate law contains only the particles involved in that step. A classic example is the reaction of hydrogen with bromine: the equation H₂ + Br₂ → 2 HBr suggests order 1 in each, but the measured rate law is fractional and complicated because a radical chain mechanism operates. Only for elementary reactions that really occur in a single collision do order and stoichiometric coefficients coincide. That is why, conversely, the measured rate law gives valuable clues about the mechanism.

What is the unit of the rate constant k?+

The unit of k depends on the overall order of the reaction, because the product k·[A]^m·[B]^n must always come out in mol/(L·s). For a zero-order reaction, k itself is in mol/(L·s). For first order one concentration cancels: k has the unit s⁻¹, which is convenient because k then relates directly to the half-life via t½ = ln 2/k. Second order requires L/(mol·s), third order L²/(mol²·s). Conversely, the unit of a given k immediately reveals the overall order; this is a popular exam trick and a good self-check when calculating.

What do zero, first and second order mean intuitively?+

For zero order the rate is constant and independent of concentration, for example when a catalyst surface or an enzyme is saturated: material is processed as fast as possible. For first order, v is proportional to the concentration of a single substance; radioactive decay and many decompositions follow this pattern with a constant half-life. For second order two particles must collide, either two identical ones (v = k·[A]²) or two different ones (v = k·[A]·[B]); here the half-life grows as the reaction proceeds. The order thus describes how strongly the reaction responds to concentration changes and reveals something about the underlying mechanism.

How are the rate law and the Arrhenius equation connected?+

The two equations split the description of the reaction rate between them. The rate law v = k·[A]^m·[B]^n describes, at fixed temperature, how v depends on the concentrations. The entire temperature dependence sits in the rate constant k, and that is exactly what the Arrhenius equation k = A·e^(−E_A/(R·T)) describes. If you raise the temperature, the orders m and n stay the same, but k grows exponentially, roughly doubling per 10 K as a rule of thumb. For complete problems you combine both: first determine k at the desired temperature via Arrhenius, then insert the concentrations into the rate law. This is how chemists cleanly separate concentration and temperature effects.

Retain Rate Law (Reaction Order) for exams

Create a curated FSRS exam set for v = k·[A]^m·[B]^n: formula recall, variables, derivation, rearrangement, worked example, common mistakes and exam context.

Free · curated formula set · LaTeX · FSRS spaced repetition

How do you calculate with Rate Law (Reaction Order)?

Here is how to work through a typical Rate Law (Reaction Order) (v = k·[A]^m·[B]^n) task step by step:

  1. 1

    Task

    Doubling [A] quadruples v, [B] changes nothing: what is the rate law?

    Solution path

    v = k·[A]²: from 2^m = 4 follows m = 2, from the unchanged rate follows n = 0. The overall order is 2.

  2. 2

    Task

    A reaction is second order in A. At [A] = 0.2 mol/L, v = 4.0×10⁻³ mol/(L·s). Calculate k.

    Solution path

    k = v/[A]² = 4.0×10⁻³/(0.2)² = 4.0×10⁻³/0.04 = 0.10 L/(mol·s). The unit follows from the overall order 2.

v = k·[A]^m·[B]^n · 10 cards ready

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