Lincoln Index (Mark-Recapture Method)
The Lincoln-Petersen index estimates the size of a population that cannot be counted completely. A first catch is marked and released; from the fraction of marked animals in the second catch the total number follows.
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Formula
N = \frac{M \cdot C}{R}Variables & units – Lincoln Index (Mark-Recapture Method)
| Symbol | Meaning | Unit |
|---|---|---|
| N | estimated total size of the population | individuals |
| M | individuals marked and released in the first catch | individuals |
| C | total number of individuals in the second catch | individuals |
| R | marked individuals recaptured in the second catch | individuals |
Derivation & background – Lincoln Index (Mark-Recapture Method)
The method rests on a proportion: the fraction of marked individuals in the population (M/N) equals the fraction of marked individuals in the second catch (R/C), that is M/N = R/C, rearranged N = M·C/R. Frederick Lincoln (1930) and Carl Petersen shaped the method. Assumptions: closed population (no births, deaths, immigration or emigration between catches), good mixing, marking without effect on survival or catchability. For small R the estimate is strongly biased; then one uses the Chapman correction N = (M+1)(C+1)/(R+1) − 1.
Exam blueprint
Validity range
Applies to a closed, well-mixed population where marking does not affect survival or catchability.
Derivation steps
The proportion of marked individuals in the whole population equals their proportion in the second catch.
- 1Set up the proportion: M/N = R/C.
- 2Solve for N: N = M·C/R.
Rearrangements
Chapman correction (small recapture)
Reduces the bias when R is small.
Required recapture from an estimated size
Rearranging N = M·C/R; helps in planning the experiment.
Task variant
M = 40 marked fish. Second catch C = 50, of which R = 8 marked. How large is the population?
N = (40·50)/8 = 2000/8 = 250 fish. Chapman: N = (41·51)/9 − 1 = 232.3 − 1 ≈ 231.
M = 60 marked snails, recapture C = 90 with R = 18 marked. Determine N.
N = (60·90)/18 = 5400/18 = 300 snails.
Common mistakes
Confusing C and R.
C is the entire second catch, R only the marked individuals recaptured in it.
Applying the formula to an open population.
Births, deaths or migration between catches distort the estimate.
Trusting the raw estimate at very small R.
Small R biases strongly upward; then use the Chapman correction.
Assuming marked individuals do not remix.
Between catches enough time is needed for even mixing.
Exam context
- Typical in ecology: estimating the abundance of mobile animals (fish, snails, insects) with the mark-recapture method.
These mistakes cost points in real exams. The set drills them until they stick.
Formula cluster
Population ecology
Connects abundance estimation, proportions and model assumptions.
Worked example
You catch M = 40 fish, mark and release them. In the second catch there are C = 50 fish including R = 8 marked ones. Then N = (40·50)/8 = 2000/8 = 250 fish. The Chapman correction gives N = (41·51)/9 − 1 = 2091/9 − 1 ≈ 231.
Applications
Ecology (abundance estimation of animal populations), fisheries biology, wildlife management, nature conservation, epidemiology (estimating hidden case numbers)
Quanta exam set
Curated exam set for "Lincoln Index (Mark-Recapture Method)":
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Which formula describes Lincoln Index (Mark-Recapture Method)?
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How do you rearrange N = (M·C) / R for Chapman correction (small recapture)?
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Which common mistake happens with Lincoln Index (Mark-Recapture Method)?
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Frequently asked questions about Lincoln Index (Mark-Recapture Method)
How does the mark-recapture method work?+
You catch a first group of animals, mark them inconspicuously and release them again. After a while, during which the marked animals mix evenly with the rest, you catch another group. In this second catch you count how many marked animals are present. The idea is a proportion: the fraction of marked animals in the second catch equals the fraction of marked animals in the whole population. From this follows the formula N = M·C/R with the marked animals M, the entire second catch C and the marked ones recaptured in it R. The larger the fraction of marked animals in the second catch, the smaller the estimated population. This lets you estimate the size of populations you cannot count completely, such as fish in a pond.
How do you calculate the population size with the Lincoln index?+
You insert the three measured numbers into the formula N = M·C/R. M is the number of animals marked and released in the first catch, C the total number in the second catch and R the number of marked animals recaptured in the second catch. Example: you mark M = 40 fish. In the second catch there are C = 50 fish, of which R = 8 are marked. Then N = (40·50)/8 = 2000/8 = 250 fish. It is important not to confuse C and R: C is the entire second catch, R only the marked part of it. For small R the estimate becomes inaccurate and tends to be too high; then you use the Chapman correction N = (M+1)(C+1)/(R+1) − 1, which for the same example gives about 231.
Which conditions must the mark-recapture method meet?+
The method assumes a closed population: between the two catches there must be no births, deaths, immigration or emigration, otherwise the proportion no longer holds. In addition, the marked animals must mix evenly with the unmarked ones so that the sample is representative; this needs enough time between the catches. The marking must affect neither survival nor catchability: marked animals must not be more conspicuous to predators, not shyer and not easier to recatch. Marks must also not be lost. Finally, every animal should have the same catch probability. If these conditions are violated, the estimate is biased. In practice one chooses markings and time intervals so that the assumptions are met as well as possible, and uses extended models if needed.
Why is the Lincoln index inaccurate with a small recapture?+
The recapture R is in the denominator of the formula N = M·C/R. If R is small, even small counting differences strongly affect the result: whether you recatch 2 or 3 marked animals changes the estimate considerably. In addition, the simple formula is systematically biased upward for small R, it overestimates the population on average. The reason lies in the statistics of drawing: with few recaptures the estimated fraction of marked animals is more random and biased in expectation. Therefore one uses the Chapman correction N = (M+1)(C+1)/(R+1) − 1, which markedly reduces this bias and works even when R = 0. In principle you should choose M and C large enough to recatch enough marked animals, usually at least about ten, to obtain reliable estimates.
What is the mark-recapture method used for in practice?+
The method serves wherever populations cannot be counted completely because the animals are mobile, hidden or too numerous. In fisheries biology it estimates fish stocks in lakes and rivers to set catch quotas. In wildlife management it records mammal or bird populations for conservation, often with rings, ear tags or camera traps as marking. For insects and snails it determines local population sizes in ecological studies. Even in epidemiology the same principle is used to estimate the unknown number of disease cases by comparing two independent registers. The great advantage is that a complete count is unnecessary and even two samples yield a usable estimate. The precondition remains that the assumptions of the method are sufficiently met, otherwise the result is biased.
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How do you calculate with Lincoln Index (Mark-Recapture Method)?
Here is how to work through a typical Lincoln Index (Mark-Recapture Method) (N = (M·C) / R) task step by step:
- 1
Task
M = 40 marked fish. Second catch C = 50, of which R = 8 marked. How large is the population?
Solution path
N = (40·50)/8 = 2000/8 = 250 fish. Chapman: N = (41·51)/9 − 1 = 232.3 − 1 ≈ 231.
- 2
Task
M = 60 marked snails, recapture C = 90 with R = 18 marked. Determine N.
Solution path
N = (60·90)/18 = 5400/18 = 300 snails.