Resistivity (Conductor Resistance)
The resistance of a wire grows with its length and falls with its cross-section; the resistivity ρ is the material constant.
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Formula
R = \rho \cdot \frac{l}{A}Variables & units – Resistivity (Conductor Resistance)
| Symbol | Meaning | Unit |
|---|---|---|
| R | Resistance of the conductor | Ω |
| ρ | Resistivity (copper: 0.0178) | Ω·mm²/m |
| l | Length of the conductor | m |
| A | Cross-sectional area of the conductor | mm² |
Derivation & background – Resistivity (Conductor Resistance)
The formula refines Ohm measurements of 1826: a wire twice as long acts like two resistors in series (R doubles), a doubled cross-section like two parallel conductors (R halves). ρ depends on material and temperature: for metals it rises with temperature (about +0.4 %/K for copper), while constantan is nearly temperature-independent. Typical values in Ω·mm²/m: silver 0.016, copper 0.0178, aluminium 0.027, iron about 0.10.
Exam blueprint
Validity range
Applies to homogeneous conductors of constant cross-section at constant temperature. For metals ρ rises with temperature (copper: about +0.4 % per K); for semiconductors it falls.
Derivation steps
Length acts like a series connection, cross-section like a parallel connection.
- 1Two equal wire pieces in series double R, so R ∝ l.
- 2Two equal wires side by side halve R, so R ∝ 1/A; the material constant ρ gives R = ρ·l/A.
Rearrangements
Cross-section
Sizing cables for a maximum permitted resistance.
Length
For example the wire length of a coil from a resistance measurement.
Material constant
Identifying a material from resistance and geometry.
Task variant
What cross-section does a 20 m copper cable need for at most 0.2 Ω?
A = ρ·l/R = 0.0178 × 20/0.2 = 1.78 mm², so choose the standard size 2.5 mm².
An iron wire (ρ = 0.10 Ω·mm²/m, A = 0.5 mm²) has R = 4 Ω. How long is it?
l = R·A/ρ = 4 × 0.5/0.10 = 20 m.
Common mistakes
Mixing mm² and m².
Stay consistent: with ρ in Ω·mm²/m use A in mm²; with ρ in Ω·m use A in m².
Forgetting the outgoing and return conductor in cables.
For the voltage drop the round-trip length (twice the run) counts.
Reading ρ as mass density.
Here ρ is the electrical resistivity, a different quantity with the same symbol.
Ignoring the temperature dependence.
Table values usually refer to 20 °C; hot conductors have noticeably more resistance.
Exam context
- Tasks combine the formula with Ohm law and power loss: choosing cross-sections, voltage drop of long lines and sizing heating wires.
These mistakes cost points in real exams. The set drills them until they stick.
Formula cluster
DC circuits
Extends Ohm law by geometry and material dependence.
Worked example
Copper cable (ρ = 0.0178 Ω·mm²/m): l = 50 m, A = 1.5 mm²: R = 0.0178 × 50/1.5 ≈ 0.59 Ω.
Applications
Sizing cable cross-sections (house wiring), heating wires, strain gauges, resistance thermometers (Pt100), overhead lines
Quanta exam set
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How do you rearrange R = ρ·l/A for Cross-section?
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Frequently asked questions about Resistivity (Conductor Resistance)
How do you calculate the resistance of a wire?+
Multiply the resistivity of the material by the length and divide by the cross-section: R = ρ·l/A. Using the practical unit ρ in Ω·mm²/m you insert l in metres and A in mm² and obtain R directly in ohms. Example: 50 m of copper wire (ρ = 0.0178 Ω·mm²/m) with a 1.5 mm² cross-section has R = 0.0178 × 50/1.5 ≈ 0.59 Ω. The formula shows the two levers: a longer wire has more resistance, a thicker one less. Always check whether your table value is given in Ω·mm²/m or in Ω·m; A must then be in mm² or m² accordingly.
Why do thick cables have less resistance?+
A thick conductor acts like many thin conductors side by side, i.e. like a parallel circuit. In a parallel circuit the reciprocals of the resistances add, so the total resistance drops. Doubling the cross-section exactly halves R, which is why A sits in the denominator. Microscopically, more parallel paths are available to the electrons; the current spreads over more cross-sectional area. In practice this is why car starter cables are thick: at currents of 100 A and more a thin cable would develop too much heat according to P = I²·R and its voltage drop would cripple the starter. Length works the other way round: double length, double resistance (series connection).
What cable cross-section is needed for a long line?+
Rearrange the formula for the cross-section: A = ρ·l/R_max, where R_max is the highest permissible line resistance. Example: a 20 m copper feed line is to have at most 0.2 Ω: A = 0.0178 × 20/0.2 = 1.78 mm², so you choose the next standard size 2.5 mm². Two subtleties matter in practice: first, the current flows out and back, so for the voltage drop the round-trip length counts. Second, the conductor heats up under load, and the resistivity of copper rises by about 0.4 % per kelvin, so a hot line has noticeably more resistance than the 20 °C table promises.
What does resistivity tell you about a material?+
ρ is the material parameter of electrical conduction, independent of the geometry of the specific wire. Small values mean good conductors: silver leads at 0.016 Ω·mm²/m, just ahead of copper (0.0178) and aluminium (0.027); that is why wiring is copper and overhead lines are the lighter aluminium. Iron sits noticeably higher at about 0.10. Alloys like constantan (0.5) are deliberately poor conductors with an almost temperature-independent ρ, ideal for measuring resistors. Heating elements like Kanthal use high ρ for targeted heat generation. Insulators like glass reach values beyond 10¹⁶ Ω·mm²/m. A span of more than 20 orders of magnitude makes ρ one of the most variable material properties of all.
Why does the resistance of metals rise with temperature?+
In metals the number of free electrons is practically independent of temperature, but the lattice ions vibrate more strongly when hot. The drifting electrons therefore collide more often with the vibrating ions, their mean free path shrinks, and the resistance rises, for copper by about 0.4 % per kelvin. An incandescent lamp shows the effect drastically: cold, its filament has only about one tenth of its operating resistance, so the switch-on current is correspondingly high. Semiconductors behave the other way round because heat releases additional charge carriers there. Metrology exploits this contrast: platinum resistance thermometers (Pt100) measure temperature via the metallic rise, NTC thermistors via the semiconductor fall.
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How do you calculate with Resistivity (Conductor Resistance)?
Here is how to work through a typical Resistivity (Conductor Resistance) (R = ρ·l/A) task step by step:
- 1
Task
What cross-section does a 20 m copper cable need for at most 0.2 Ω?
Solution path
A = ρ·l/R = 0.0178 × 20/0.2 = 1.78 mm², so choose the standard size 2.5 mm².
- 2
Task
An iron wire (ρ = 0.10 Ω·mm²/m, A = 0.5 mm²) has R = 4 Ω. How long is it?
Solution path
l = R·A/ρ = 4 × 0.5/0.10 = 20 m.