Mathematics · Calculus / Integration

Antiderivatives and Basic Integrals

The power rule of integration yields antiderivatives: raise the exponent by 1 and divide by the new exponent.

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Formula

LaTeX: \int x^{n} \, dx = \frac{x^{n+1}}{n+1} + C \quad (n \neq -1)
Dimensionless (calculus)

Variables & units – Antiderivatives and Basic Integrals

SymbolMeaningUnit
xVariable of integrationdimensionless
nExponent (n ≠ −1)dimensionless
CConstant of integration (any real number)dimensionless

Derivation & background – Antiderivatives and Basic Integrals

Integration reverses differentiation: F is called an antiderivative of f if F′ = f. The power rule of integration mirrors the power rule of differentiation. Important basic integrals: ∫e^x dx = e^x + C, ∫1/x dx = ln|x| + C (the special case n = −1), ∫sin x dx = −cos x + C, ∫cos x dx = sin x + C. Since constants vanish when differentiating, every antiderivative is determined only up to +C.

Exam blueprint

Validity range

The power rule of integration holds for all real n ≠ −1; for n = −1 the antiderivative is ln|x| + C. Antiderivatives are unique only up to a constant C.

Derivation steps

Integration reverses differentiation: differentiate the candidate and compare.

  1. 1Differentiate x^(n+1)/(n+1): (n+1)·xⁿ/(n+1) = xⁿ ✓.
  2. 2Since constants vanish when differentiating, every antiderivative is determined only up to +C.

Rearrangements

Special case n = −1

The power rule would divide by 0; the logarithm steps in.

Exponential and trigonometry

The basic exam integrals; watch the sign for sin.

Linear substitution

Inner linear function: divide by a instead of multiplying.

Task variant

Find all antiderivatives of f(x) = 4x³ − 2x + 5.

Term by term: F(x) = x⁴ − x² + 5x + C. Check: F′(x) = 4x³ − 2x + 5 ✓.

Find the antiderivative of f(x) = e^(2x) through the point (0|1).

F(x) = ½e^(2x) + C. F(0) = ½ + C = 1, so C = ½. Result: F(x) = ½e^(2x) + ½.

Common mistakes

Lowering the exponent when integrating, as in differentiating.

Integration raises: xⁿ → x^(n+1)/(n+1).

Dropping the +C.

Without C infinitely many antiderivatives are missing; initial conditions fix C.

Integrating 1/x with the power rule.

n = −1 is the special case: ln|x| + C.

Writing ∫sin x dx = cos x + C.

Correct: −cos x + C; differentiate to check.

Exam context

  • First step of every integral task: find the antiderivative, then insert the limits.

These mistakes cost points in real exams. The set drills them until they stick.

Formula cluster

Integral calculus

Basic integrals, fundamental theorem and area calculation build on each other.

Worked example

∫(3x² + 2) dx = x³ + 2x + C. Check by differentiating: (x³ + 2x + C)′ = 3x² + 2 ✓. Likewise: ∫cos x dx = sin x + C, since (sin x)′ = cos x.

Applications

Area and volume calculation, reconstructing totals from rates of change, physics (distance from velocity), probability densities

Quanta exam set

Curated exam set for "Antiderivatives and Basic Integrals":

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Which formula describes Antiderivatives and Basic Integrals?

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How do you rearrange ∫xⁿ dx = xⁿ⁺¹/(n+1) + C for Special case n = −1?

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Which common mistake happens with Antiderivatives and Basic Integrals?

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+ 7 more cards: units, variables, derivation, example, exam task

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Scientific sources

Common notations & search queries

Integral x^n dx = x^(n+1)/(n+1)+CStammfunktion bildenaufleitenGrundintegrale TabelleStammfunktion x^2Integral Regelnantiderivative power ruleunbestimmtes Integral

Related formulas

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Frequently asked questions about Antiderivatives and Basic Integrals

How do I find the antiderivative of a power function?+

Reverse the power rule of differentiation: raise the exponent by 1, then divide by the new exponent. xⁿ becomes x^(n+1)/(n+1) + C, valid for all n ≠ −1. Constant factors stay, sums are handled term by term. Example: f(x) = 4x³ − 2x + 5 has antiderivatives F(x) = x⁴ − x² + 5x + C. The rule also works for negative and fractional exponents: ∫x⁻² dx = −x⁻¹ + C and ∫√x dx = ∫x^(1/2) dx = (2/3)x^(3/2) + C. Safest check: differentiate the result, it must give exactly the integrand. Only the case n = −1 drops out; there the antiderivative is ln|x| + C.

Why does every antiderivative need the +C?+

Because the derivative of every constant is zero. If F is an antiderivative of f, then so are F + 7 or F − 123, since the constant vanishes without trace when differentiating. The set of all antiderivatives is therefore a whole family of vertically shifted graphs, and the +C stands for these infinitely many possibilities. C is pinned down only by an extra condition, such as "the graph passes through (0|1)": for f(x) = e^(2x), F(x) = ½e^(2x) + C, and F(0) = 1 forces C = ½. In a definite integral, however, C cancels in F(b) − F(a), so there you may drop it.

Which basic integrals must I know by heart for the final exam?+

The core set is short: the power rule ∫xⁿ dx = x^(n+1)/(n+1) + C for n ≠ −1, the special case ∫1/x dx = ln|x| + C, the exponential ∫eˣ dx = eˣ + C with the variant ∫e^(kx) dx = (1/k)e^(kx) + C, and the trigonometric pair ∫sin x dx = −cos x + C and ∫cos x dx = sin x + C. Add the structural rules: integrate term by term, pull constant factors out front, and for an inner linear function f(ax + b) divide by a. With this toolbox you cover almost all mandatory-part integrals; more complicated products are handled by integration by parts. Regular self-check: differentiate backwards.

What is the difference between "aufleiten" and integrating?+

In German classrooms "aufleiten" is student slang for finding an antiderivative, i.e. reversing differentiation; the proper term is indefinite integration. Mathematics distinguishes two things precisely: the indefinite integral ∫f(x) dx denotes the set of all antiderivatives F + C. The definite integral ∫ₐᵇ f(x) dx, by contrast, is a number, defined as a limit of rectangle sums, measuring signed areas. The fundamental theorem connects both worlds: you obtain the number by evaluating any antiderivative at the limits, F(b) − F(a). In exams use the term antiderivative; "aufleiten" is understood by everyone but counts as colloquial.

How do I integrate f(ax + b), for example e^(3x) or sin(2x)?+

Use the linear substitution rule: if F is an antiderivative of f, then ∫f(ax + b) dx = (1/a)·F(ax + b) + C. The inner linear function stays, and you divide by its slope a instead of multiplying by it as in differentiation. Examples: ∫e^(3x) dx = (1/3)e^(3x) + C, ∫sin(2x) dx = −(1/2)cos(2x) + C, ∫(4x + 1)⁵ dx = (1/4)·(4x + 1)⁶/6 + C. Checking by differentiating shows why: the chain rule produces the factor a, which the 1/a cancels again. Caution: this convenient rule holds ONLY for linear inner functions; for ∫e^(x²) dx it fails, such an integral has no elementary antiderivative.

Retain Antiderivatives and Basic Integrals for exams

Create a curated FSRS exam set for ∫xⁿ dx = xⁿ⁺¹/(n+1) + C: formula recall, variables, derivation, rearrangement, worked example, common mistakes and exam context.

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How do you calculate with Antiderivatives and Basic Integrals?

Here is how to work through a typical Antiderivatives and Basic Integrals (∫xⁿ dx = xⁿ⁺¹/(n+1) + C) task step by step:

  1. 1

    Task

    Find all antiderivatives of f(x) = 4x³ − 2x + 5.

    Solution path

    Term by term: F(x) = x⁴ − x² + 5x + C. Check: F′(x) = 4x³ − 2x + 5 ✓.

  2. 2

    Task

    Find the antiderivative of f(x) = e^(2x) through the point (0|1).

    Solution path

    F(x) = ½e^(2x) + C. F(0) = ½ + C = 1, so C = ½. Result: F(x) = ½e^(2x) + ½.