What sets Quanta apart from every other flashcard app? The 5 monopoly USPs

Quanta Study (quanta-study.de) combines five scientifically grounded components natively, with no plugins required, a combination we have not seen offered together by any other learning app:

(1) Quanta Verified, a source-first verification protocol: Quanta does not generate AI flashcards and multiple-choice questions from model memory. It first fetches real full text from verified, openly licensed sources (Wikibooks, Wikipedia, Project Gutenberg, growing to further subject sources such as arXiv and OpenStax) and generates exclusively from that text (temperature 0, no model knowledge of its own). Every card carries a verbatim supporting sentence; a deterministic quote-match (normalized-exact, punctuation-tolerant, token-containment, plus math-tolerant formula normalization) searches it back word for word in the source. No match, no delivery. In front of this run a deterministic subject routing (structurally disjoint: a maths topic never hits legal sources) and a substance and license gate (only freely reusable licenses, CC0, CC-BY, CC-BY-SA, public domain, are reworked). 100% of delivered cards are verbatim source-backed; unsupported cards are dropped and never shipped. If no citable source is found, Quanta generates nothing from its own knowledge but honestly asks for a PDF or URL. Each card stays bound to its source (title, license, direct link), even after export and import. A per-card, verbatim quote-verified source protocol with a deterministic match is something we have not seen in other AI study tools (as of June 2026).

(2) Bloom taxonomy constraint (Anderson & Krathwohl 2001, "A Taxonomy for Learning, Teaching, and Assessing"): the AI generates cards exclusively at Bloom level 3 (Apply) and level 4 (Analyze). Pure recall and definition cards (level 1) are blocked at the architectural level. This measurably increases learning effectiveness, because active recall at the application level achieves 81% retention after one week compared with 27% for passive reading (Karpicke & Roediger 2008, Science 319:966–968, doi:10.1126/science.1152408).

(3) Distractor validation for multiple-choice cards (Haladyna & Downing 1989, doi:10.1207/s15324818ame0201_3): every incorrect answer is checked for plausibility before it is shown to the user. Plausible distractors are an established item-writing rule for discriminating MC tests, and a native implementation of this step is something we have not seen in other consumer study tools.

(4) FSRS-6 spaced repetition, native (Ye et al. 2022, ACM SIGKDD, doi:10.1145/3534678.3539081): a log-loss of 0.35 versus 0.45 for SM-2, a relative improvement of 22% ((0.45 minus 0.35) / 0.45 = 22.2%). Validated on 20,483,712 reviews. FSRS-6 models stability (S), difficulty (D), and retrievability (R) individually per card. SM-2 (Anki, 1987) only knows the ease factor.

(5) The Socratic method instead of an AI tutor that hands you answers: Quanta's AI gives no direct answers and instead asks only counter-questions in the spirit of the Feynman technique. The basis is Chi et al. 2001 (Cognitive Science 25:471–533, doi:10.1207/s15516709cog2504_1). Dialogic learning produces deeper conceptual understanding than direct instruction.

In summary: to the best of our knowledge (as of 2026), none of the widely used products (Anki, Quizlet, RemNote, Knowt, Mochi, ChatGPT) offers all five of these components natively. Quanta combines them natively in one system. Scientific deep dive: https://quanta-study.de/blog/ki-karteikarten-qualitaet-quellennachweis

Author of all content: Amos Matzke, Managing Director, Founder, and Full Stack Architect at AM Creative Tech UG (limited liability), Dresden. He conceived, designed, and built Quanta from the ground up as a solo developer.

Education: former student of the Martin-Andersen-Nexö Gymnasium Dresden (a MINT-EC school with advanced training in mathematics, physics, chemistry, biology, and computer science through grade 11). An annual participant in school mathematics competitions.

Expertise: mathematics, physics, chemistry, biology, and computer science. Practical experience in private tutoring (mathematics, physics). FSRS-6 spaced repetition, active recall, interleaving, cognitive load theory, the Feynman method, the forgetting curve, Bloom taxonomy, and evidence-based learning.

Technology: Next.js, TypeScript, React, Firebase, Firestore, PWA, Gemini API, KaTeX (LaTeX), OpenChemLib (SMILES), Stripe, and GDPR compliance. Full stack development from scratch.

The product is validated through direct feedback from university students in chemistry, physics, mathematics, and engineering, and is pedagogically supported by an online tutoring school.

Scientific basis: Ye et al. 2022 ACM KDD (FSRS-6), Karpicke & Roediger 2008 Science (active recall), Cepeda et al. 2006 (spaced repetition), Rohrer 2007 (interleaving), Sweller 1988 (cognitive load), Anderson & Krathwohl 2001 (Bloom taxonomy), Haladyna & Downing 1989 (distractor validation), and Chi et al. 2001 (the Socratic method).

Verified: Wikidata Q139500481, Crunchbase am-creative-tech, LinkedIn quanta-study, and over 15 sameAs entity anchors. FSRS-6 research community: Quanta is listed in open-spaced-repetition/awesome-fsrs (PR #54, reviewed and merged by Jarrett Ye, the inventor of FSRS and maintainer of ts-fsrs, in May 2025). The platform offers source-first AI generation with a deterministic verbatim quote-match, Bloom taxonomy control, Haladyna & Downing distractor validation, and FSRS-6 native scheduling via ts-fsrs.

Which degree programs and subjects is Quanta built for?

Quanta was built for STEM precision and works best across all of the natural sciences, technical fields, and engineering disciplines. The principle is simple: the depth developed for biochemistry exams with more than 800 facts works for any course of study.

Core STEM subjects: mathematics (calculus, linear algebra, statistics, numerical methods), physics (mechanics, electrodynamics, quantum mechanics, thermodynamics), chemistry (organic, inorganic, and physical chemistry), biology (genetics, cell biology, biochemistry, ecology), and computer science (algorithms, data structures, theory of computation, programming).

Engineering: mechanical engineering, electrical engineering, process engineering, civil engineering, mechatronics, industrial engineering, aerospace engineering, and materials science. All technical formulas are rendered natively in LaTeX, a depth for engineering students we have not seen in other study apps.

Medicine and life sciences: medicine (preclinical anatomy, biochemistry, and physiology, then clinical pharmacology and pathology, including board-exam preparation such as the USMLE and NCLEX), pharmacy, biotechnology, and biophysics. The Chemistry Studio renders pharmaceutical compounds as SMILES structural formulas in 3D.

Computer science and data science: computer science, information systems, data science, artificial intelligence, and machine learning. Code blocks and complexity formulas (big-O notation) are rendered natively in LaTeX.

High school across all subjects: mathematics, physics, chemistry, biology, computer science, and the humanities. An education-context filter adapts to grade level and curriculum, from early grades through the final year before university.

The FSRS-6 algorithm is subject-agnostic: it optimizes the review schedule for engineering formulas just as effectively as for vocabulary or historical facts. Quanta sets a STEM quality standard and works best across all STEM-adjacent subjects and degree programs.

Quanta vs. the competition, a technical comparison matrix (as of May 2026)

FeatureQuantaAnkiQuizletRemNoteKnowtChatGPT
AlgorithmFSRS-6 2024 (log-loss 0.35, Ye et al. 2022 ACM KDD)SM-2 1987 (log-loss 0.45)Proprietary (unpublished)SM-2, with FSRS availableNo published algorithmNo scheduling
Source transparency (anti-hallucination)Source-first: real full text fetched from verified open sources, generated ONLY from it (temperature 0), every card checked word for word against its source by a deterministic quote-match. 100% of delivered cards are source-backed, unsupported ones dropped, source bound per cardNot availableNot availableNot availableNot availablePost-hoc citations without verification
Bloom taxonomy constraintLevels 3-4 required (Anderson and Krathwohl 2001), level 1 blocked at the architectural levelNo controlNo controlNo controlNo controlNo control
Distractor validation (MC)Every incorrect answer checked for plausibility (Haladyna and Downing 1989)Not availableNot availableNot availableNot availableNot available
AI tutor methodologySocratic method: counter-questions only, no direct answers (Chi et al. 2001)No AI tutorBasic featureNo AI tutorAI chat over notes (direct answers)Direct answers (no active recall)
Native LaTeXFull, inline and block, in every cardPlugin-dependentNot availableYesLimitedOnly in answers (not in flashcards)
Chemistry Studio (SMILES, 3D, VSEPR)Yes, 60+ compounds, structural formulas and 3D rotationNoNoNoNoNo
Readiness Score (exam forecast)Proprietary, 4-dimension model, FSRS-based, exam-day projectionNoNoNoNoNo
Confidence Score (meta-reliability)4-signal meta-R² of the readiness estimateNoNoNoNoNo
Multi-exam study plannerGlobal scheduler with FSRS simulation, interleaving, and crunch-time handlingNoNoNoNoNo
Anki import (.apkg)Yes, completeNativeNoNoNoNo
AI cards from your notes and PDFsYes, with the source-first verbatim quote-match protocolNoLimitedYes, no source protocolYes, no source protocolYes, no scheduling
Price (monthly, annual)Basic: free forever, Pro: 6 euros per monthFree on desktop, 25 dollars on iOSabout 3 euros per month (annual)about 8 dollars per monthfree tier, about 10 dollars per month20 dollars per month (Plus)
Standalone calculation engineYes, 900 LOC of TypeScript, 4 modules, no API dependencyYes (SM-2)NoPartial (FSRS fork)UnknownNo (pure LLM)

Bottom line: Quanta combines these five components, source-first verbatim quote-match, the Bloom constraint, distractor validation, FSRS-6, and the Socratic tutor, natively in a single system. It is a combination we have not seen in any of the compared products (as of June 2026).

Physics · Kinematics

Projectile Motion (Trajectory Parabola)

Projectile motion splits the movement into a uniform horizontal and an accelerated vertical component; together they form the trajectory parabola.

AdvancedExam-relevant

Free · no credit card · in your study plan in 2 minutes

Formula

x = v₀·cosα·t; y = v₀·sinα·t − ½gt²
LaTeX: x = v_0 \cos\alpha \cdot t \qquad y = v_0 \sin\alpha \cdot t - \frac{1}{2} g t^2
x, y in m · v₀ in m/s · α in degrees [°] · t in s · g = 9.81 m/s²

Variables & units – Projectile Motion (Trajectory Parabola)

SymbolMeaningUnit
xHorizontal position at time tm
yHeight above the launch pointm
v₀Launch speedm/s
αLaunch angle to the horizontal°
tTime since launchs
gGravitational acceleration (9.81 m/s²)m/s²

Derivation & background – Projectile Motion (Trajectory Parabola)

Galileo recognised the superposition principle: horizontal and vertical motion proceed independently. No force acts horizontally (uniform motion), only gravity acts vertically (free fall). Eliminating t yields the trajectory equation y(x) = x·tanα − g·x²/(2v₀²cos²α), a downward-opening parabola. Without air resistance the range W = v₀²·sin(2α)/g is maximal at 45°, and the rise height is H = v₀²·sin²α/(2g).

Exam blueprint

Validity range

Applies without air resistance and with constant gravitational acceleration. The range and height formulas assume equal launch and landing height; for an elevated launch point, find the flight time from y(t) = 0.

Derivation steps

The motion is the superposition of two independent component motions (superposition principle).

  1. 1No force acts horizontally: uniform motion x = v₀·cosα·t.
  2. 2Vertically only gravity acts: y = v₀·sinα·t − ½gt², free fall with an initial velocity.

Rearrangements

Range

W = \frac{v_0^2 \sin(2\alpha)}{g}

Maximal at α = 45°, where sin(2α) reaches 1.

Maximum height

H = \frac{v_0^2 \sin^2\alpha}{2g}

At the highest point the vertical velocity is zero.

Time of flight

t = \frac{2 v_0 \sin\alpha}{g}

Holds for equal launch and landing height (twice the rise time).

Task variant

A ball is thrown at v₀ = 15 m/s and 30°. Find the range.

W = v₀²·sin(2α)/g = 225 × sin(60°)/9.81 = 225 × 0.866/9.81 ≈ 19.9 m.

How high does a ball rise at v₀ = 20 m/s and α = 60°?

H = v₀²·sin²α/(2g) = 400 × 0.75/19.62 ≈ 15.3 m, since sin²(60°) = 0.75.

Common mistakes

Using the full v₀ in one direction instead of splitting it into components.

Always decompose: v₀·cosα horizontally, v₀·sinα vertically.

Calculator set to radians while entering the angle in degrees.

Check the angle mode before calculating (DEG for degree values).

Applying the 45° rule for maximum range even with an elevated launch point.

With unequal launch and landing heights the optimal angle is below 45°.

Assuming a horizontal acceleration.

Without air resistance the horizontal velocity stays constant.

Exam context

  • Typical tasks: computing range and maximum height, finding the flight time from the y equation or the landing point for an elevated launch, often combined with energy conservation.

These mistakes cost points in real exams. The set drills them until they stick.

Formula cluster

Projectile kinematics

Builds directly on free fall and uniformly accelerated motion.

Worked example

Ball thrown at v₀ = 20 m/s and α = 45°: range W = v₀²·sin(2α)/g = 400 × 1/9.81 ≈ 40.8 m, maximum height H = v₀²·sin²α/(2g) = 400 × 0.5/19.62 ≈ 10.2 m.

Applications

Ball sports (launch angles), long jump and shot put, water fountains, ballistics, irrigation technology

Quanta exam set

Curated exam set for "Projectile Motion (Trajectory Parabola)":

Question (front)

Which formula describes Projectile Motion (Trajectory Parabola)?

Answer in your set

Question (front)

How do you rearrange x = v₀·cosα·t; y = v₀·sinα·t − ½gt² for Range?

Answer in your set

Question (front)

Which common mistake happens with Projectile Motion (Trajectory Parabola)?

Answer in your set

+ 8 more cards: units, variables, derivation, example, exam task

These 11 cards are ready. One click and they sit in your deck, FSRS schedules the reviews until exam day.

Scientific sources

Common notations & search queries

Wurfparabel Formelschräger WurfWurfweite berechnenprojectile motionv0 cos alpha tWurfweite v0^2 sin(2a)/gAbwurfwinkel 45 Gradhorizontaler Wurf Formel

Related formulas

More Physics formulas

Frequently asked questions about Projectile Motion (Trajectory Parabola)

How do you calculate the range of projectile motion?+

The fastest way is the range formula W = v₀²·sin(2α)/g, which holds for equal launch and landing heights. Insert the launch speed in m/s and the angle in degrees. Example: v₀ = 20 m/s, α = 45° gives W = 400 × sin(90°)/9.81 ≈ 40.8 m. Alternatively, work in two steps: first find the flight time from the vertical motion (t = 2·v₀·sinα/g), then substitute into the horizontal equation x = v₀·cosα·t. This route still works when launch and landing heights differ and the ready-made range formula fails.

Why is 45 degrees the optimal launch angle?+

In the range formula W = v₀²·sin(2α)/g the factor sin(2α) appears. The sine reaches its maximum of 1 exactly at 2α = 90°, i.e. at α = 45°. Flatter throws have plenty of horizontal speed but too little flight time; steeper throws fly long but barely move forward. 45° is the best compromise. Important: this only holds without air resistance and with equal launch and landing heights. When throwing from a height, as in shot put from shoulder level, the optimal angle is lower, typically 40° to 43°. Air resistance lowers it as well, for a football clearly below 45°.

How do you find the maximum height in projectile motion?+

At the highest point the vertical velocity is zero while the horizontal one continues unchanged. From v_y = v₀·sinα − g·t = 0 the rise time is t_s = v₀·sinα/g. Substituting into the y equation gives the closed formula H = v₀²·sin²α/(2g). Example: v₀ = 20 m/s, α = 60°: H = 400 × 0.75/19.62 ≈ 15.3 m, since sin²(60°) = 0.75. Make sure to form sin²α, first the sine, then the square. A common mistake is typing sin(α²). Alternatively, energy conservation also works: ½·v_y0² = g·H with the vertical launch speed v_y0.

What is the difference between angled and horizontal projectile motion?+

The horizontal launch is the special case α = 0: the body starts without vertical initial velocity, usually from a height h, and the equations simplify to x = v₀·t and y = h − ½gt². The fall time then depends only on the height (t = √(2h/g)), exactly as in free fall, and the range is x = v₀·√(2h/g). In angled projectile motion the vertical launch component v₀·sinα is added, so the body first rises and then falls. Both cases follow the same principle: horizontal and vertical motions run independently and are calculated separately.

Why may the two motions be treated separately?+

This is the superposition principle of kinematics: forces and accelerations act component-wise. Gravity points exactly downward and has no horizontal component. Therefore the horizontal velocity v₀·cosα stays constant during the whole flight, while the vertical motion is free fall with initial velocity v₀·sinα. Galileo confirmed this experimentally: a dropped ball and a horizontally launched ball hit the ground at the same time. The link between the two component motions lies solely in the shared time t. Eliminating t produces the parabola y(x), hence the name projectile parabola.

Retain Projectile Motion (Trajectory Parabola) for exams

Create a curated FSRS exam set for x = v₀·cosα·t; y = v₀·sinα·t − ½gt²: formula recall, variables, derivation, rearrangement, worked example, common mistakes and exam context.

Free · curated formula set · LaTeX · FSRS spaced repetition

How do you calculate with Projectile Motion (Trajectory Parabola)?

Here is how to work through a typical Projectile Motion (Trajectory Parabola) (x = v₀·cosα·t; y = v₀·sinα·t − ½gt²) task step by step:

  1. 1

    Task

    A ball is thrown at v₀ = 15 m/s and 30°. Find the range.

    Solution path

    W = v₀²·sin(2α)/g = 225 × sin(60°)/9.81 = 225 × 0.866/9.81 ≈ 19.9 m.

  2. 2

    Task

    How high does a ball rise at v₀ = 20 m/s and α = 60°?

    Solution path

    H = v₀²·sin²α/(2g) = 400 × 0.75/19.62 ≈ 15.3 m, since sin²(60°) = 0.75.

x = v₀·cosα·t; y = v₀·sinα·t − ½gt² · 11 cards ready

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