Avogadro Constant (Particle Number)
The Avogadro constant N_A links the amount of substance to the actual particle number: one mole contains 6.022×10²³ particles, n moles correspondingly n times as many.
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Formula
N = n \cdot N_AVariables & units – Avogadro Constant (Particle Number)
| Symbol | Meaning | Unit |
|---|---|---|
| N | Particle number (atoms, molecules, ions) | dimensionless |
| n | Amount of substance | mol |
| N_A | Avogadro constant (6.02214076×10²³) | mol⁻¹ |
Derivation & background – Avogadro Constant (Particle Number)
Since 2019 the exactly fixed value N_A = 6.02214076×10²³ mol⁻¹ has defined the mole in the SI system. Named after Amedeo Avogadro, whose 1811 hypothesis states that equal gas volumes at the same pressure and temperature contain equal numbers of particles. Jean Perrin determined N_A experimentally via Brownian motion (Nobel Prize 1926).
Exam blueprint
Validity range
Applies universally to any particle type; all that matters is which particles are counted (atoms, molecules, ions, electrons).
Derivation steps
Since 2019 the mole has been defined directly via the fixed particle number N_A.
- 1By definition one mole contains exactly 6.02214076×10²³ particles.
- 2n moles accordingly contain n times as many: N = n·N_A.
Rearrangements
Amount of substance
From the particle number back to moles.
Mass of one particle
Connects molar mass and single-particle mass.
Task variant
How many molecules are in 0.25 mol of water?
N = n·N_A = 0.25 · 6.022×10²³ ≈ 1.51×10²³ molecules.
How heavy is a single water molecule (M = 18.02 g/mol)?
m_T = M/N_A = 18.02/(6.022×10²³) ≈ 2.99×10⁻²³ g.
Common mistakes
Not specifying the particle type.
1 mol of H₂O contains N_A molecules but 3·N_A atoms; always state what is counted.
Copying the power of ten of N_A incorrectly.
N_A ≈ 6.022×10²³ mol⁻¹; an order-of-magnitude check exposes typos immediately.
Giving the particle number N a unit such as mol.
N is a pure count; only n carries the unit mol.
Exam context
- Combined tasks with n = m/M: from weighed mass to particle number and back, also in nuclear physics contexts.
These mistakes cost points in real exams. The set drills them until they stick.
Formula cluster
Counting particles
The bridge between mole calculations and the particle model.
Worked example
0.25 mol of water contains N = n·N_A = 0.25 × 6.022×10²³ ≈ 1.51×10²³ molecules. Conversely: 3.011×10²⁴ particles correspond to n = N/N_A = 5.0 mol.
Applications
Particle-number calculations, SI definition of the mole, crystallography, semiconductor doping, radioactivity (activity from the number of nuclei)
Quanta exam set
Curated exam set for "Avogadro Constant (Particle Number)":
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Which formula describes Avogadro Constant (Particle Number)?
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How do you rearrange N = n·N_A for Amount of substance?
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Which common mistake happens with Avogadro Constant (Particle Number)?
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Scientific sources
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Frequently asked questions about Avogadro Constant (Particle Number)
How do you calculate the particle number from the amount of substance?+
Multiply the amount of substance by the Avogadro constant: N = n·N_A with N_A = 6.022×10²³ mol⁻¹. Example: 0.25 mol of water contain N = 0.25·6.022×10²³ ≈ 1.51×10²³ molecules. If a mass is given instead of an amount, proceed in two steps: first n = m/M, then N = n·N_A. Thus 9.0 g of water (n = 0.50 mol) contain about 3.0×10²³ molecules. The result is a pure count without a unit. Always check the order of magnitude: everyday quantities of a substance almost always lie between 10²² and 10²⁵ particles; a result like 10¹² would be a sure sign of a calculation error.
Why does the Avogadro constant have exactly this value?+
The value was historically chosen so that particle mass and molar mass share the same numerical value: one carbon-12 atom weighs 12 u, one mole of carbon-12 weighs practically 12 g. For that, the number of particles per mole must be exactly the reciprocal of the atomic mass unit in grams. Originally the mole was therefore defined via 12 g of carbon-12, and N_A was measured, among others by Jean Perrin via Brownian motion and later with high precision using nearly perfect silicon single-crystal spheres. Since the 2019 SI reform the tables have turned: N_A = 6.02214076×10²³ mol⁻¹ is fixed exactly and in turn defines the mole.
How heavy is a single atom or molecule?+
Divide the molar mass by the Avogadro constant: m_T = M/N_A. A water molecule accordingly weighs 18.02 g/mol divided by 6.022×10²³ mol⁻¹, i.e. about 2.99×10⁻²³ g. A carbon atom comes to 12.01/6.022×10²³ ≈ 1.99×10⁻²³ g. Such numbers show why particles are not weighed individually but in mole portions: only 10²³ particles add up to weighable gram quantities. It works the same way in reverse: from a particle mass in u you directly get the molar mass in g/mol, because the numerical values are equal. This conversion likes to appear hidden in exams, for instance in mass-spectrometry tasks or nuclear physics.
Does N = n·N_A count atoms or molecules?+
You decide that yourself, and that is exactly why you must always state the particle type. The formula gives the number of the particles to which the amount of substance refers. One mole of water contains 6.022×10²³ water molecules, but each molecule consists of three atoms, so it holds 3·6.022×10²³ ≈ 1.8×10²⁴ atoms. One mole of oxygen gas O₂ contains N_A molecules and 2·N_A oxygen atoms. For salts you count formula units or ions directly: one mole of CaCl₂ delivers one mole of Ca²⁺ and two moles of Cl⁻ ions. Exam questions often target precisely this difference; so read carefully whether molecules, atoms or ions are asked for.
What does Avogadro's law state for gases?+
Avogadro's hypothesis of 1811 states: equal volumes of any gases contain equal numbers of particles at the same pressure and temperature. That is remarkable because the particles themselves can differ hugely in mass. From this follows the molar volume: at standard temperature and pressure (0 °C, 1013 hPa) one mole of any ideal gas occupies about 22.4 L, at 25 °C and 1 bar about 24.8 L (from V = nRT/p = 8.314·298.15/100,000 m³). This lets you translate gas volumes directly into amounts: 11.2 L of hydrogen at STP are 0.5 mol. The law appears as V ∝ n in the ideal gas law pV = nRT and explains why reaction equations for gases also describe volume ratios.
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How do you calculate with Avogadro Constant (Particle Number)?
Here is how to work through a typical Avogadro Constant (Particle Number) (N = n·N_A) task step by step:
- 1
Task
How many molecules are in 0.25 mol of water?
Solution path
N = n·N_A = 0.25 · 6.022×10²³ ≈ 1.51×10²³ molecules.
- 2
Task
How heavy is a single water molecule (M = 18.02 g/mol)?
Solution path
m_T = M/N_A = 18.02/(6.022×10²³) ≈ 2.99×10⁻²³ g.