Chemistry · Spectroscopy

Beer-Lambert Law (Photometry)

The Beer-Lambert law relates the absorbance of a solution to its concentration and path length, the basis of UV/Vis spectroscopy and quantitative analysis.

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Formula

LaTeX: A = \varepsilon \cdot c \cdot d
A dimensionless, ε in L·mol⁻¹·cm⁻¹, c in mol/L, d in cm

Variables & units – Beer-Lambert Law (Photometry)

SymbolMeaningUnit
AAbsorbance = lg(I₀/I)dimensionless
εMolar base-10 absorption coefficient (substance-specific)L·mol⁻¹·cm⁻¹
cMolar concentration of the absorbing substancemol/L
dPath length of the cuvettecm

Derivation & background – Beer-Lambert Law (Photometry)

Johann Lambert (1760) and August Beer (1852) formulated the law independently. It is valid in the linear range (A < 1.0). Deviations occur at high concentrations. ELISA, HPLC detection and glucose sensors are based on it.

Exam blueprint

Validity range

Applies in the linear concentration range, with monochromatic light and without scattering or chemical interactions.

Derivation steps

Each thin layer absorbs the same relative fraction of light.

  1. 1Intensity decreases exponentially with path length and concentration.
  2. 2The base-10 logarithm of transmission gives A = εcd.

Rearrangements

Concentration from absorbance

Cuvette length and the unit of ε must match.

Task variant

Why do very high absorbances become inaccurate?

Too little light reaches the detector; scattering and instrument errors dominate.

Common mistakes

Mixing ε units and cuvette length in cm/m.

If ε is in L·mol⁻¹·cm⁻¹, d must be in cm.

Exam context

  • Often used in calibration curves, UV/Vis evaluation and concentration determination.

These mistakes cost points in real exams. The set drills them until they stick.

Worked example

A protein (ε = 40,000 L·mol⁻¹·cm⁻¹), cuvette d = 1 cm, c = 10⁻⁵ mol/L: A = 40,000 · 10⁻⁵ · 1 = 0.40. Transmittance: T = 10⁻⁰·⁴⁰ ≈ 40 %.

Applications

UV/Vis spectroscopy, protein-concentration determination (BCA, Bradford), ELISA, enzyme assays, water analysis

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Which formula describes Beer-Lambert Law (Photometry)?

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How do you rearrange A = ε·c·d for Concentration from absorbance?

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Which common mistake happens with Beer-Lambert Law (Photometry)?

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Scientific sources

Common notations & search queries

A=epsilon*c*dA=ε*c*dE=ε*c*dExtinktion FormelLambert-Beer GesetzBeer-Lambert lawAbsorption Spektroskopie FormelAbsorbanz Formel UV Vis

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Frequently asked questions about Beer-Lambert Law (Photometry)

How do you calculate the absorbance with the Lambert-Beer law?+

Multiply the molar extinction coefficient ε, the concentration c and the path length d: A = ε·c·d. The absorbance A is dimensionless. Insert ε in L·mol⁻¹·cm⁻¹, c in mol/L and d in cm so the units cancel. Example: a protein with ε = 40 000 L·mol⁻¹·cm⁻¹ in a 1 cm cuvette at c = 10⁻⁵ mol/L gives A = 40 000·10⁻⁵·1 = 0.40. From the absorbance the transmission follows via T = 10^(−A), here T = 10⁻⁰·⁴ ≈ 40 percent. Make sure the unit of ε and the path length match, usually both in centimetres.

How do you determine an unknown concentration with the Lambert-Beer law?+

Rearrange the law for the concentration: c = A/(ε·d). You measure the absorbance A of the sample in the photometer, know the molar extinction coefficient ε of the substance and the path length d of the cuvette. From these three quantities the concentration follows. In practice one often records a calibration curve by measuring the absorbance of several known concentrations; its slope is ε·d. From the absorbance of the unknown sample the concentration is then read off via the line. Watch for consistent units and stay in the linear range. This method is a standard procedure of quantitative analysis, for example to determine the concentration of dyes or proteins.

Why do very high absorbance values become inaccurate?+

At high absorbance only very little light reaches the detector, because almost everything is absorbed. At A = 2 only 1 percent of the light gets through, at A = 3 only 0.1 percent. This small residual signal is dominated by stray light, noise and instrument imprecision, so small measurement errors cause large relative errors in the concentration. In addition the linear relationship loses its validity at high concentrations, because particles influence each other and the law holds only for dilute solutions. Therefore one measures most accurately in the absorbance range between about 0.1 and 1. If the sample is too concentrated, you dilute it instead of measuring an unreliable high absorbance.

What does the molar extinction coefficient mean?+

The molar extinction coefficient ε is a substance-specific quantity and states how strongly a substance absorbs light of a certain wavelength. It has the unit L·mol⁻¹·cm⁻¹ and describes the absorbance per concentration and path length. A large value means that even small concentrations absorb strongly, which allows sensitive measurements. ε depends on the substance, the wavelength of the light and partly on the solvent; therefore one usually measures at the absorption maximum, where ε is largest. Dyes and proteins with extended electron systems often have very high extinction coefficients. ε is the proportionality factor that links concentration and measured absorbance in the Lambert-Beer law.

When does the Lambert-Beer law no longer apply?+

The law holds only under several conditions: dilute solutions, monochromatic light and no scattering or chemical interactions. At high concentrations the absorbance deviates from linearity, because the particles influence each other and the extinction coefficient is no longer constant. If the light is not single-coloured, different wavelengths with different ε mix and distort the result. Turbid or scattering samples, chemical reactions, association or dissociation of the dissolved particles also lead to deviations. A common mistake is to apply the law at too high concentrations. For clear, dilute solutions in a photometer, by contrast, it gives very reliable, linear relationships.

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How do you calculate with Beer-Lambert Law (Photometry)?

Here is how to work through a typical Beer-Lambert Law (Photometry) (A = ε·c·d) task step by step:

  1. 1

    Task

    Why do very high absorbances become inaccurate?

    Solution path

    Too little light reaches the detector; scattering and instrument errors dominate.