Mathematics · Calculus

Taylor Series

The Taylor series expresses a function as a power series around an expansion point a.

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Formula

LaTeX: f(x) = \sum_{n=0}^{\infty} \frac{f^{(n)}(a)}{n!} (x-a)^n
Dimensionless (calculus)

Variables & units – Taylor Series

SymbolMeaningUnit
f⁽ⁿ⁾(a)n-th derivative of f at the point adimensionless
n!Factorial of ndimensionless
aExpansion pointdimensionless

Derivation & background – Taylor Series

Brook Taylor 1715, Colin Maclaurin 1742 (special case a = 0). Of fundamental importance: every smooth function can be approximated locally by polynomials. eˣ = 1 + x + x²/2! + x³/3! + ... (converges everywhere).

Exam blueprint

Validity range

The Taylor series describes functions locally; equality with the function requires convergence and a vanishing remainder.

Derivation steps

A polynomial is chosen so that value and derivatives match at the expansion point.

  1. 1Set P(x)=Σ c_n(x-a)^n.
  2. 2From P^{(n)}(a)=f^{(n)}(a), c_n=f^{(n)}(a)/n!.

Rearrangements

Taylor coefficient

Each coefficient stores one derivative at the expansion point.

Task variant

Why is linearization the first Taylor part?

For n=0 and n=1 one obtains f(a)+f'(a)(x-a).

Common mistakes

Ignoring radius of convergence and remainder.

A Taylor series is not automatically equal to the function everywhere.

Exam context

  • Typical in approximations, error estimates, limits and physics linearizations.

These mistakes cost points in real exams. The set drills them until they stick.

Worked example

sin(x) around a = 0: sin(x) = x − x³/6 + x⁵/120 − ... For x = 0.1: sin(0.1) ≈ 0.1 − 0.000167 ≈ 0.09983. Exact: 0.09983...

Applications

Numerical mathematics, physics (approximations), signal processing, calculator implementations

Quanta exam set

Curated exam set for "Taylor Series":

Question (front)

Which formula describes Taylor Series?

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Question (front)

How do you rearrange f(x) = Σ f⁽ⁿ⁾(a)/n! · (x−a)ⁿ for Taylor coefficient?

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Question (front)

Which common mistake happens with Taylor Series?

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Scientific sources

Common notations & search queries

f(x)=Σ f^n(a)/n! (x-a)^nTaylorreihe FormelTaylor PolynomMaclaurin ReiheTaylor EntwicklungTaylor seriesPotenzreihenentwicklung Funktion

Related formulas

More Mathematics formulas

Frequently asked questions about Taylor Series

How do you represent a function as a Taylor series?+

You expand the function around a point a and sum terms of the form f^(n)(a)/n! · (x−a)^n over all n from zero to infinity. Each coefficient contains the n-th derivative at the expansion point, divided by the factorial of n. In practice you first compute the derivatives at a, divide by n! and multiply by the power (x−a)^n. Example sine around a = 0: sin x = x − x³/6 + x⁵/120 − …, because the derivatives alternate between sine and cosine. For x = 0.1 even the first approximation gives sin(0.1) ≈ 0.09983, very close to the exact value.

Why is linearization the first part of a Taylor series?+

If you truncate the Taylor series after the term for n = 1, you are left with f(a) + f′(a)·(x−a). This is exactly the equation of the tangent to the function at the point a, that is the linear approximation or linearization. The constant term f(a) fixes the function value, the linear term f′(a)·(x−a) the slope. Near the expansion point this line describes the function very well, because higher powers of (x−a) are still very small there. Physics and engineering use this approximation constantly, for example for small deflections of a pendulum, where sin x is replaced by x. Higher Taylor terms improve the accuracy further.

When does a Taylor series no longer represent the whole function?+

A Taylor series describes a function only locally and does not automatically agree with it everywhere. Two conditions must be met: the series must converge, that is stay within its radius of convergence, and the remainder must tend to zero as the number of terms grows. Outside the radius of convergence the series diverges and gives useless values. There are even functions whose Taylor series converges but not to the function itself. A common mistake is to assume that finitely many terms are exact everywhere. For practical approximations you therefore choose an expansion point near the point of interest and estimate the error via the remainder.

What are Taylor series used for in practice?+

Taylor series replace complicated functions with polynomials that are much easier to compute with. Calculators and computers evaluate sine, cosine, exponential and logarithm functions internally via such series, because only addition and multiplication are needed. In physics one linearizes difficult relationships with the first term, for example the pendulum equation for small angles. In error analysis Taylor is used to estimate how measurement uncertainties propagate. Limits of indeterminate form can also be found through series expansion. Finally Taylor is used in numerical methods to approximate derivatives and integrals. The idea of locally replacing a function with a polynomial is one of the most powerful tools of calculus.

What is the difference between a Taylor and a Maclaurin series?+

A Maclaurin series is simply the special case of a Taylor series with the expansion point a = 0. While the general Taylor series expands around an arbitrary point a and contains powers of (x−a), the Maclaurin series expands around the origin and contains pure powers of x. This makes the formulas simpler, because the derivatives only need to be evaluated at zero. The well-known series for e^x, sin x and cos x are all Maclaurin series. You choose the expansion point so that it lies near the point of interest and the derivatives are easy to compute there; for many standard functions this is exactly the origin.

Retain Taylor Series for exams

Create a curated FSRS exam set for f(x) = Σ f⁽ⁿ⁾(a)/n! · (x−a)ⁿ: formula recall, variables, derivation, rearrangement, worked example, common mistakes and exam context.

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How do you calculate with Taylor Series?

Here is how to work through a typical Taylor Series (f(x) = Σ f⁽ⁿ⁾(a)/n! · (x−a)ⁿ) task step by step:

  1. 1

    Task

    Why is linearization the first Taylor part?

    Solution path

    For n=0 and n=1 one obtains f(a)+f'(a)(x-a).