Physics · Quantum Mechanics

Heisenberg Uncertainty Principle

The uncertainty principle sets a fundamental limit on how precisely position and momentum can be determined simultaneously, not a measurement problem but a property of quantum nature.

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Formula

LaTeX: \Delta x \cdot \Delta p \geq \frac{\hbar}{2}
Δx in m, Δp in kg·m/s, ℏ = h/(2π) ≈ 1.055 × 10⁻³⁴ J·s

Variables & units – Heisenberg Uncertainty Principle

SymbolMeaningUnit
ΔxStandard deviation of positionm
ΔpStandard deviation of momentumkg·m/s
Reduced Planck constant (h/2π)J·s

Derivation & background – Heisenberg Uncertainty Principle

Werner Heisenberg (1927) showed that the more precisely the position is known, the less precisely the momentum is known, and vice versa. This is fundamental, not a matter of measurement technique. The energy-time uncertainty: ΔE·Δt ≥ ℏ/2.

Exam blueprint

Validity range

Applies to quantum states and describes standard deviations, not instrument errors.

Derivation steps

Position and momentum are Fourier-conjugate quantities; sharper position means broader momentum spectrum.

  1. 1A wavefunction with narrow position spread needs many wave numbers.
  2. 2Since p = ℏk, this becomes larger momentum uncertainty.

Rearrangements

Minimum momentum uncertainty

The inequality gives a lower bound, not an exact value for every state.

Task variant

What happens to Δp if Δx is halved?

The minimum Δp doubles.

Common mistakes

Interpreting uncertainty as measurement inaccuracy.

It is a fundamental property of the quantum state.

Exam context

  • Typical in electron localization, atomic size and tunnelling contexts.

These mistakes cost points in real exams. The set drills them until they stick.

Worked example

An electron (m = 9.11×10⁻³¹ kg) localised to Δx = 10⁻¹⁰ m: Δp ≥ ℏ/(2·Δx) = 1.055×10⁻³⁴/(2·10⁻¹⁰) ≈ 5.3×10⁻²⁵ kg·m/s. Uncertainty in velocity: Δv ≈ 5.8×10⁵ m/s.

Applications

Quantum chemistry, the tunnel effect, atomic structure, MRI spectroscopy, semiconductor physics

Quanta exam set

Curated exam set for "Heisenberg Uncertainty Principle":

Question (front)

Which formula describes Heisenberg Uncertainty Principle?

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Question (front)

How do you rearrange Δx · Δp ≥ ℏ/2 for Minimum momentum uncertainty?

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Which common mistake happens with Heisenberg Uncertainty Principle?

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Scientific sources

Common notations & search queries

delta x * delta p >= hbar/2Δx Δp ≥ ℏ/2dx*dp >= h/4piHeisenbergsche UnschärferelationUnschärfeprinzip Formeluncertainty principleHeisenberg Unsicherheitsprinzip

Related formulas

More Physics formulas

Frequently asked questions about Heisenberg Uncertainty Principle

What does the Heisenberg uncertainty principle state?+

The uncertainty principle states that the position and momentum of a particle cannot both be determined with arbitrary precision at the same time. The product of the two uncertainties has a lower bound: Δx·Δp ≥ ℏ/2, with the reduced Planck constant ℏ ≈ 1.055×10⁻³⁴ J·s. The more precisely the position is fixed, the larger the momentum uncertainty inevitably becomes and vice versa. This limit is not a matter of poor instruments but a fundamental property of the quantum nature. Δx and Δp are the standard deviations of the respective distributions. For everyday objects the limit is completely negligible because of the tiny ℏ, but for electrons and other quantum particles it is decisive.

Is the uncertainty a measurement error or something fundamental?+

The uncertainty is not an imprecision of the instruments but a fundamental property of the quantum states themselves. A particle does not simultaneously possess an exactly sharp position and an exactly sharp momentum; these quantities are not physically defined together with arbitrary precision at all. Δx and Δp are standard deviations of the probability distributions that describe the state. Even with perfect instruments the limit Δx·Δp ≥ ℏ/2 would remain. The reason is that position and momentum are Fourier-conjugate quantities: a spatially tightly localized wave function needs many different wave numbers and thus a broad momentum spectrum. Treating this interpretation as a mere measurement error is a widespread misconception.

How do you calculate the minimum momentum uncertainty?+

Rearrange the uncertainty relation for Δp: Δp ≥ ℏ/(2·Δx). The minimum momentum uncertainty is obtained when you take the equals sign. Insert the reduced Planck constant ℏ ≈ 1.055×10⁻³⁴ J·s and the position uncertainty Δx in metres. Example: an electron localized to Δx = 10⁻¹⁰ m has Δp ≥ 1.055×10⁻³⁴/(2·10⁻¹⁰) ≈ 5.3×10⁻²⁵ kg·m/s. Through Δp = m·Δv this gives a speed uncertainty of about 5.8×10⁵ m/s. If you halve the position uncertainty, the minimum momentum uncertainty doubles, because the two quantities are inversely proportional to each other. Make sure to use ℏ and not h.

Why do you not notice the uncertainty in everyday life?+

Because the reduced Planck constant ℏ, at about 1.055×10⁻³⁴ J·s, is unimaginably small. For macroscopic objects the limit set by Δx·Δp ≥ ℏ/2 is so tiny that it vanishes completely against any practically achievable measurement precision. A car or a ball has such a large momentum that the associated momentum and position uncertainty lies billions of times below any detection threshold. Therefore everyday objects appear sharply localized and with a definite speed. Only for extremely light particles such as electrons, whose momentum is small and whose wavelength is large, does the uncertainty become significant and determine the behaviour, for example the size of atoms and the stability of the electron shell.

What is the difference between h and ℏ in the uncertainty relation?+

In the uncertainty relation Δx·Δp ≥ ℏ/2 it is the reduced Planck constant ℏ, not the ordinary h. Both are linked through ℏ = h/(2π), so they differ by the factor 2π ≈ 6.28. With h = 6.626×10⁻³⁴ J·s you get ℏ ≈ 1.055×10⁻³⁴ J·s. A common mistake is to accidentally insert h instead of ℏ; then the result is too large by exactly the factor 2π. The reduced ℏ appears wherever angular frequencies or angular momenta play a role, while h appears for example in E = h·f and in the de Broglie relation λ = h/p. Check carefully in every formula which constant is required.

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Create a curated FSRS exam set for Δx · Δp ≥ ℏ/2: formula recall, variables, derivation, rearrangement, worked example, common mistakes and exam context.

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How do you calculate with Heisenberg Uncertainty Principle?

Here is how to work through a typical Heisenberg Uncertainty Principle (Δx · Δp ≥ ℏ/2) task step by step:

  1. 1

    Task

    What happens to Δp if Δx is halved?

    Solution path

    The minimum Δp doubles.