Read half-reaction, reference electrode and conditions first
Every entry represents reduction, meaning electron gain, and is referenced to the standard hydrogen electrode, SHE. Its E° is 0 V by convention. An electrode potential is relative to a reference electrode, not a separately measured absolute voltage of a piece of metal.[1]
The tabulated value belongs to its stated chemical form and phase. Br2(aq) and Br2(l) are different references; a metal ion with complexing ligands is not automatically the free aqueous ion. Added entries apply at 25 °C, or 298.15 K, with standard activities and gas fugacity referenced to 1 bar where relevant.
A concentration of 1 mol/L corresponds to activity 1 only with the matching convention and idealization. Real electrolytes may depart appreciably. Conditions therefore specify activities rather than simply saying “all solutions 1 M”.[3]
Reduce at the cathode and oxidize at the anode
Both inserted table values are reduction potentials.[1]
Reduction occurs at the cathode and oxidation at the anode. For a spontaneous galvanic direction under standard conditions, the cathode has the higher compatible reduction potential. Positive cell voltage initially describes the thermodynamics of the written overall reaction.
In a galvanic cell, external electrons flow from anode to cathode; their signs are negative and positive respectively. Electrolysis can drive a reaction in reverse. Anode still means oxidation and cathode reduction, although their electrical signs differ.
Balance electrons without multiplying potentials
To add half-reactions, equalize their electron counts by multiplying stoichiometric coefficients. Potential remains unchanged because it is energy per transferred charge. Doubling reaction extent and transferred charge doubles free energy but not their ratio.[2]
Reversing the overall reaction reverses cell-voltage sign. Halving or doubling the overall reaction in the same direction leaves E° unchanged while n and ΔᵣG° scale. Reverse a half-reaction to describe oxidation, or use unchanged reduction values in cathode-minus-anode. Do not mix the two sign methods.
Acidic and alkaline rows describe different reactions
Acidic permanganate reduction uses 8 H+ and 5 electrons to form Mn2+. The added alkaline form uses 3 electrons, produces MnO2 and forms 4 OH−. Products, electron count and standard potential differ. The name “permanganate” alone is therefore insufficient.[1]
An acidic standard entry also requires standard H+ activity 1; an alkaline standard entry requires OH− activity 1. An arbitrary acidic or alkaline laboratory solution does not automatically meet these conditions. Account for pH through the reaction quotient of the full half-reaction.
Acidic and alkaline forms cannot be treated as a unit conversion. For multiple half-cells, species and equilibria must match the actual chemical environment; relevant thermodynamically possible side reactions may need additional balancing.
From standard potential to actual activity
Q is dimensionless and belongs to the reaction in its written reduction direction.[2]
Q has product activities in the numerator and reactant activities in the denominator, each raised to its stoichiometric exponent. Electrons are not inserted as dissolved species. Pure condensed phases in the matching reference contribute 1; gases contribute fugacity ratios and solutions their activities.
This half-cell has n = 1; equal activities give E = E°.
The factor 0.05915935 V belongs to 298.15 K. At another temperature, recalculate RT/F; E° itself may also vary with temperature. For a complete cell, use its overall Q or calculate both electrode potentials and subtract.
Two original calculations: cell energy and activity shift
Tin(II) reduces iron(III) in the standard model
- Given
- 298.15 K, standard activities; Fe3+/Fe2+: +0.771 V; Sn4+/Sn2+: +0.151 V. Assume compatible separated half-cells.
- Find
- Find the reaction, E° and ΔᵣG° per mole of the written reaction.
Double iron reduction and reverse tin reduction.
Subtract unchanged reduction potentials.
Calculate free energy using n = 2 and F = Nae.
Result: E° = 0.620 V; ΔᵣG° ≈ −119.642 kJ/mol of the written overall reaction.
Check: Left charge is 2·3 + 2 = 8; right charge is 2·2 + 4 = 8. Atoms and charge balance with n = 2. Negative free energy agrees with positive voltage.
An iron potential above its standard value
- Given
- 298.15 K; E°Fe = 0.771 V versus SHE; aFe2+ = 0.020, aFe3+ = 0.080; no complex formation in the model.
- Find
- Find reversible half-cell potential.
Form the reduction quotient.
Apply Nernst with one electron.
Check the direction of the shift.
Result: E ≈ 0.80662 V versus SHE, about 35.62 mV above the standard potential.
Check: Q < 1 makes ln Q negative, so E exceeds E°. Equal activities would give Q = 1 and no shift. Activities are problem assumptions.
Three exercises on medium, electrons and signs
Combine acidic MnO4−/Mn2+ (+1.507 V, 5 e−) as cathode with Fe3+/Fe2+ (+0.771 V) as anode. Find E° and n.
Show hint
Oxidize five Fe2+ and include H+ in the balance.
Show solution and calculation
E° = 0.736 V and n = 5.
Overall: MnO4− + 8 H+ + 5 Fe2+ → Mn2+ + 4 H2O + 5 Fe3+.
Both sides have charge +17.
Ni2+/Ni is −0.257 V and Ag+/Ag is +0.7996 V. Find spontaneous standard direction and voltage.
Show hint
The higher reduction potential is the cathode.
Show solution and calculation
Ni + 2 Ag+ → Ni2+ + 2 Ag.
Arithmetic E° = 0.7996 − (−0.257) = 1.0566 V, reasonably rounded to about 1.057 V.
Double silver coefficients, not its potential.
Reverse the Fe/Sn overall reaction from the example, then double it. What are E° and electron count?
Show hint
Reversal changes sign; scaling changes n.
Show solution and calculation
E° = −0.620 V and n = 4. ΔᵣG° is positive and twice the original magnitude; E° does not become −1.240 V.
Zinc–silver comparison using one consistent data set
- Given
- 298.15 K and standard activities; OpenStax Table 17.1: Ag+/Ag +0.7996 V, Zn2+/Zn −0.7618 V.
- Find
- Check the familiar zinc–silver calculation using both values from the same source.
Silver is reduced and zinc oxidized.
Subtract unchanged potentials.
Result: Arithmetic result 1.5614 V with this OpenStax data set. The previous guide obtained 1.5622 V using OpenStax silver and separately documented NIST zinc −0.7626 V.
Check: The 0.8 mV difference follows from data selection, not a sign error. Do not present the calculations as one precise data set. n = 2; reaction coefficients do not change E°.
Thermodynamic voltage and actual operation
Reversible voltage is not automatically terminal voltage under load. Internal resistance, mass transport and activation overpotentials affect operation. A favourable reaction may be slow; surface oxides or passivation can further inhibit it. A tabulated potential alone gives neither current nor reaction rate.
Liquid-junction potentials and reference electrodes influence measurement. An Ag/AgCl electrode at a real chloride activity does not automatically have standard potential +0.22233 V. Converting a measurement requires the electrode filling, temperature and reference scale.
Preserve source precision and report rounding honestly
Lookup rows retain decimal places from their specifically named source. Different sources may tabulate slightly different values or conventions. Do not mix them as though they formed one high-precision data set. Existing iron and zinc entries use NIST values; added OpenStax entries are identified separately and do not overwrite them.[1][5]
Many arithmetic digits can document a calculation without proving small measurement uncertainty. Round the final result according to data quality and purpose. In equilibrium calculations, a small potential difference can produce a large change in the predicted constant; use a consistent, adequately documented data set.
Sources for this explanation
Quanta · Updated October 1, 2026
- OpenStax Chemistry 2e §17.3, Table 17.1
- OpenStax Chemistry 2e §17.4: Nernst, free energy and equilibrium
- IUPAC Gold Book: activity
- BIPM: SI Brochure, 9th edition
- NIST JPCRD: zinc standard potentials at 298.15 K
Editorial responsibility: Quanta Study editorial team
Review scope
This explanation, 3 worked examples and 3 exercises are available in German and English. Structure, source references and mathematical notation undergo automated checks. Calculations, model assumptions and both language versions receive a separate AI review.
An internal human subject review is documented for an earlier release of this page. That confirmation does not apply automatically to the revised explanation and new exercises.
An independent, named human subject review has not yet been documented. Our exercise numbers are worked examples, rather than measurements published by the cited sources.
Editorial responsibility, sources and methodsCite this reference page
Quanta. Selected standard reduction potentials. Updated October 1, 2026. https://quanta-study.de/en/formula-sheet/tables/standard-reduktionspotentiale
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