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In a direct proportion, the quotient y/x is constant, so y changes by the same factor as x.
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Formula
x and y use their context units; k has units of y per x.
| Symbol | Meaning | Unit |
|---|---|---|
| Dependent quantity | context-dependent | |
| Independent quantity | context-dependent | |
| Constant of proportionality | context-dependent |
y=kx,\quad k=\frac{y}{x}Original schematic by Quanta
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The graph is a straight line through the origin and y/x stays equal to k for x≠0. The model assumes no fixed offset; a linear function y=mx+b with b≠0 is not directly proportional. A unit-rate method is one way to calculate with the same ratio.
The relation must pass through the origin; adding a fixed offset makes it linear but not directly proportional.
If y/x stays constant, call that quotient k.
Find the constant of variation
For this quotient form, x must be nonzero.
Four notebooks cost €10. What do seven cost at the same unit price? Use a unit-rate proportion.
One notebook costs €10/4=€2.50.
Seven cost 7·€2.50=€17.50.
Unit-rate method: divide by 4, then multiply by 7.
Calling any straight-line relation proportional.
Check that the line passes through (0,0) and that y/x is constant.
Formula cluster
A constant quotient and a graph through the origin identify direct proportion.
Four kilograms of apples cost €10. The unit rate is k=10/4=€2.50/kg, so 7 kg cost 2.50·7=€17.50. Check: both price-to-mass ratios equal €2.50/kg.
Unit rates, scales, constant speed, prices, and scaling with a fixed ratio.
Here is how to work through a typical Direct Proportion (y = kx) task step by step:
Task
Four notebooks cost €10. What do seven cost at the same unit price? Use a unit-rate proportion.
Solution path
One notebook costs €10/4=€2.50.
Seven cost 7·€2.50=€17.50.
Unit-rate method: divide by 4, then multiply by 7.
In a direct proportion, the quotient y/x stays constant when x is nonzero. If x doubles, y doubles; if x triples, y also triples. For example, 4 kg cost €10, so the unit price is 10/4=€2.50/kg. Seven kilograms cost €17.50. Check several pairs for the same quotient. Merely increasing together is not enough: one quantity can rise without being proportional. The graph must also pass through the origin. Units help interpret the quotient: euros divided by notebooks gives a price per notebook.
With a unit-rate method, first calculate the cost of one unit and then scale to the requested amount. If 4 notebooks cost €10, one costs 10/4=€2.50. Seven then cost 7·€2.50=€17.50. This assumes the unit price stays fixed and that no base fee or bulk discount applies. Algebraically, you find the same factor k=10/4 and use y=kx. The unit-rate method and the equation are two ways to represent the same proportional relationship, not competing rules. Measured data rarely lie exactly on a line because of measurement error; the model describes the expected relationship.
The equation y=kx gives y=0 whenever x=0, so the origin (0,0) lies on its graph. A fixed base charge shifts every value: for y=2x+5, the cost is still 5 units when x=0. That relation is linear but not directly proportional. This matters in real situations, such as a taxi fare with a fixed starting fee. For measured data, a graph that appears to pass through the origin is not proof by itself; also check the ratios and measurement uncertainty. A unit-rate calculation starts from a known pair and preserves the same quotient for the requested amount.
k is the constant quotient y/x and tells you how much y corresponds to one unit of x. In a price problem it is the unit price; in uniform motion it can be speed. Its unit follows from the quantities, such as euros per notebook or metres per second. If k=€2.50 per notebook, 8 notebooks cost €20. Without context, k has no fixed unit. Also do not confuse k with the slope of every straight line: direct proportion requires a line through the origin. A nonzero intercept represents a fixed starting amount and rules out direct proportion, even if the line rises.
Use direct proportion only when the ratio remains constant. A one-time fee, tiered pricing, or a change in work rate can violate the assumption. Check whether doubling x also doubles y and whether y would be zero at x=0. For a fixed job with a changing number of workers, an inverse relationship may apply instead. With measured data, rounding can make ratios differ slightly; judge the model and measurement precision rather than demanding exact equality for every value. State which conditions keep k constant, such as unit price or speed.
Quanta exam set
Curated exam set for "Direct Proportion":
Question (front)
Which formula describes Direct Proportion?
Answer in your set
Question (front)
How do you rearrange Direct Proportion for Find the constant of variation?
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Question (front)
Which common mistake happens with Direct Proportion?
Answer in your set
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Create a curated FSRS exam set for y = kx: formula recall, variables, derivation, rearrangement, worked example, common mistakes and exam context.
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