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The standard equations distinguish an ellipse from a hyperbola and relate their semiaxes to the distance of the foci.
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Formula
x, y, a, b and c use the same length unit; eccentricity e=c/a is dimensionless.
| Symbol | Meaning | Unit |
|---|---|---|
| Point coordinates relative to the centre | length unit | |
| Semiaxes; for an ellipse, a is the larger semiaxis | length unit | |
| Centre-to-focus distance | length unit | |
| Eccentricity c/a | dimensionless |
x^2/a^2+y^2/b^2=1, c^2=a^2-b^2;\quad x^2/a^2-y^2/b^2=1, c^2=a^2+b^2These forms assume centered conics whose axes are parallel to the coordinate axes. For an ellipse, a≥b>0 and c2=a2−b2, so 0≤e<1; for a horizontal hyperbola, a,b>0 and c2=a2+b2, so e>1. A vertical axis is obtained by interchanging x and y. Translated or rotated conics must first be expressed in the matching coordinate system.
These forms assume centered conics whose axes are parallel to the coordinate axes. For an ellipse, a≥b>0 and c2=a2−b2, so 0≤e<1; for a horizontal hyperbola, a,b>0 and c2=a2+b2, so e>1. A vertical axis is obtained by interchanging x and y. Translated or rotated conics must first be expressed in the matching coordinate system.
The standard equations distinguish an ellipse from a hyperbola and relate their semiaxes to the distance of the foci.
Ellipse focal distance
For an ellipse a≥b>0; for a hyperbola use c2=a2+b2 instead.
Rework the example for “Ellipses and Hyperbolas: Axes and Foci” and explain why the check is valid.
For an ellipse with a=5 cm and b=3 cm, c=√(25−9)=4 cm and e=0.8.
For a hyperbola with a=3 cm and b=4 cm, c=√(9+16)=5 cm.
Check: c<a for the ellipse and c>a for the hyperbola, matching the focus positions.
Ignoring an assumption of the formula: These forms assume centered conics whose axes are parallel to the coordinate axes
Check units and model conditions before substitution; then verify the result in the original relation or a limiting case.
Formula cluster
Related relations in the formula sheet: scheitelpunktform-parabel, kreisflaeche-umfang.
For an ellipse with a=5 cm and b=3 cm, c=√(25−9)=4 cm and e=0.8. For a hyperbola with a=3 cm and b=4 cm, c=√(9+16)=5 cm. Check: c<a for the ellipse and c>a for the hyperbola, matching the focus positions.
Classify conics, calculate foci, and connect analytic geometry with orbital and optical models.
Here is how to work through a typical Ellipses and Hyperbolas: Axes and Foci (Ellipse: c²=a²−b²; Hyperbel: c²=a²+b²) task step by step:
Task
Rework the example for “Ellipses and Hyperbolas: Axes and Foci” and explain why the check is valid.
Solution path
For an ellipse with a=5 cm and b=3 cm, c=√(25−9)=4 cm and e=0.8.
For a hyperbola with a=3 cm and b=4 cm, c=√(9+16)=5 cm.
Check: c<a for the ellipse and c>a for the hyperbola, matching the focus positions.
The standard equations distinguish an ellipse from a hyperbola and relate their semiaxes to the distance of the foci. The compact relation Ellipse: c2=a2−b2; Hyperbel: c2=a2+b2 shows how the defined quantities interact; x, y, a, b and c use the same length unit; eccentricity e=c/a is dimensionless. Interpretation depends on the model context: Classify conics, calculate foci, and connect analytic geometry with orbital and optical models. Also inspect whether a quantity enters linearly, quadratically, inversely or through another function. This lets you predict how the result changes before calculating. The equation is therefore both a calculation rule and a statement about the model's structure.
Assign each given value to a symbol and convert units consistently first. For an ellipse with a=5 cm and b=3 cm, c=√(25−9)=4 cm and e=0.8. For a hyperbola with a=3 cm and b=4 cm, c=√(9+16)=5 cm. Check: c<a for the ellipse and c>a for the hyperbola, matching the focus positions. Then verify the result independently: These forms assume centered conics whose axes are parallel to the coordinate axes Compare the final unit and order of magnitude with the context, and round only after completing the calculation. This check can reveal not only arithmetic mistakes but also a wrong model or a missed factor. When several quantities enter the relation, vary one mentally and ask whether the result follows the expected trend.
The key step is: These forms assume centered conics whose axes are parallel to the coordinate axes. This leads to Ellipse: c2=a2−b2; Hyperbel: c2=a2+b2. The derivation separates definitions, subject-specific assumptions and the final algebraic step; correct algebra cannot replace a missing condition. For an ellipse with a=5 cm and b=3 cm, c=√(25−9)=4 cm and e=0.8. For an ellipse, a≥b>0 and c2=a2−b2, so 0≤e<1; for a horizontal hyperbola, a,b>0 and c2=a2+b2, so e>1 Classify conics, calculate foci, and connect analytic geometry with orbital and optical models. Reconstruct the central idea before memorizing the compact form. That makes it easier to recognize when a similar-looking formula does not apply.
These forms assume centered conics whose axes are parallel to the coordinate axes. For an ellipse, a≥b>0 and c2=a2−b2, so 0≤e<1; for a horizontal hyperbola, a,b>0 and c2=a2+b2, so e>1. A vertical axis is obtained by interchanging x and y. Translated or rotated conics must first be expressed in the matching coordinate system. Also check x, y, a, b and c use the same length unit; eccentricity e=c/a is dimensionless. Violating the validity range can produce a precise but substantively wrong result. Verify that assumptions about geometry, smoothness, independence, symmetry or distribution actually hold in the problem. If a condition is not met, label the result as an approximation or choose a more general method. Extra decimal places cannot repair a model mismatch. This check matters especially when a neighbouring formula uses different assumptions.
The two relations are neighbours in the subject, but answer different questions. Ellipses and Hyperbolas: Axes and Foci: The standard equations distinguish an ellipse from a hyperbola and relate their semiaxes to the distance of the foci. Vertex Form of the Parabola: The vertex form shows the vertex S(d|e) of a parabola directly in the equation; the factor a controls opening and stretching. Choose based on the unknown and on which assumptions the data satisfy. Classify conics, calculate foci, and connect analytic geometry with orbital and optical models. As a check, use the example For an ellipse with a=5 cm and b=3 cm, c=√(25−9)=4 cm and e=0.8 and identify which extra quantity the companion relation would need. This clarifies when one equation is enough and when both belong in a solution.
Quanta exam set
Curated exam set for "Ellipses and Hyperbolas: Axes and Foci":
Question (front)
Which formula describes Ellipses and Hyperbolas: Axes and Foci?
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Question (front)
How do you rearrange Ellipses and Hyperbolas: Axes and Foci for Ellipse focal distance?
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Question (front)
Which common mistake happens with Ellipses and Hyperbolas: Axes and Foci?
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Create a curated FSRS exam set for Ellipse: c²=a²−b²; Hyperbel: c²=a²+b²: formula recall, variables, derivation, rearrangement, worked example, common mistakes and exam context.
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