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Average covalent bond enthalpies estimate a gas-phase reaction enthalpy by subtracting formed-bond energies from broken-bond energies.
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Formula
Bond enthalpies and ΔrH in kJ per mole of reaction; each bond enthalpy is per mole of bonds
| Symbol | Meaning | Unit |
|---|---|---|
| Estimated enthalpy change per stoichiometric reaction | kJ/mol | |
| Average enthalpy required for homolytic cleavage of one mole of the specified bonds | kJ/mol of bonds |
\Delta_r H\approx\sum D(\text{gebrochene Bindungen})-\sum D(\text{gebildete Bindungen})Use stoichiometric coefficients to count every bond broken in reactants and every bond formed in products: ΔrH≈ΣD(broken)−ΣD(formed). Bond enthalpies are average gas-phase values, so the result is an estimate and can differ from a value based on formation enthalpies. The approximation is most useful for comparing reaction energetics or checking the sign and scale. It is not a precise substitute for calorimetry or a thermochemical cycle, especially when molecular environments differ substantially.
A rough estimate for reactions of covalent gas-phase molecules using average bond enthalpies. Values are averages across molecules; use standard formation enthalpies or calorimetry for accurate reaction enthalpies.
Energy is absorbed to break reactant bonds and released when product bonds form.
Sum of broken bonds
The estimate remains limited by average tabulated values.
Estimate ΔrH for H2 + Cl2 → 2 HCl using D(H−H)=436, D(Cl−Cl)=243 and D(H−Cl)=431 kJ/mol.
ΔrH≈436+243−2·431=−183 kJ/mol.
Check: product bond formation releases more energy, so energy is released overall.
Subtract reactant bond enthalpies from product values or report the estimate as an exact tabulated result.
Calculate broken minus formed bonds, and state the average-value character and gas-phase reference.
Formula cluster
Bond enthalpies estimate ΔrH from bond changes; Hess’s law uses formation data for more accurate values.
For H2+Cl2→2 HCl, approximate D(H–H)=436, D(Cl–Cl)=243 and D(H–Cl)=431 kJ/mol. Thus ΔrH≈436+243−2·431=−183 kJ/mol reaction. Check: more energy is released forming H–Cl bonds than is required to break the reactant bonds.
Estimate reaction energetics from bond types when tabulated formation enthalpies are unavailable.
Here is how to work through a typical Reaction Enthalpy from Average Bond Enthalpies (ΔrH ≈ ΣD(gebrochen) − ΣD(gebildet)) task step by step:
Task
Estimate ΔrH for H2 + Cl2 → 2 HCl using D(H−H)=436, D(Cl−Cl)=243 and D(H−Cl)=431 kJ/mol.
Solution path
ΔrH≈436+243−2·431=−183 kJ/mol.
Check: product bond formation releases more energy, so energy is released overall.
Add the average enthalpies of all bonds broken in the reactants and subtract the sum for product bonds formed: ΔrH≈ΣD(broken)−ΣD(formed). For H2+Cl2→2HCl, tabulated values give 436+243−2·431=−183 kJ/mol. The negative sign indicates an exothermic reaction. Count each bond with its stoichiometric coefficient. This is an estimate because a given bond type can have different values in different molecules. For accurate work, standard formation enthalpies are preferable. Keep bond counts and stoichiometric coefficients tied to the same balanced reaction equation. Treat the result as an estimate, not a measured value.
Breaking a bond requires energy input, so its contribution is positive. Forming new bonds releases energy, so that amount is subtracted. This gives the sign rule “broken minus formed.” In HCl formation, breaking H−H and Cl−Cl costs 679 kJ per mole of reaction. Forming two H−Cl bonds releases 862 kJ. The difference, −183 kJ/mol, is negative. Reversing the order gives the wrong sign and would misclassify an exothermic reaction as endothermic. Each bond enthalpy is positive; the sign emerges only from balancing bond breaking against bond formation.
No. Tables average bonds of the same type across different molecules and chemical environments. A C−H bond in methane need not have exactly the same enthalpy as a C−H bond elsewhere. The estimate can therefore differ from calorimetry or a calculation with standard formation enthalpies. Bond enthalpy usually refers to homolytic separation of gas-phase molecules. Check physical states and whether a table gives average or molecule-specific values. The method is useful for signs and approximate magnitudes, not exact thermochemistry. Averaging explains why precise tabulated values still cannot guarantee an exact reaction enthalpy for a particular compound.
Both methods follow energy conservation but use different data. The bond-enthalpy method decomposes a reaction into bonds and uses average tabulated D values. Hess’s law instead sums standard formation enthalpies of the actual substances with their stoichiometric coefficients. The Hess calculation is usually more accurate when reliable formation data are available. Bond enthalpies are useful for comparing structural changes or when only bond data are provided. Do not mix the two kinds of tables because they describe different reference processes. Both methods must use the same standard states and reaction direction for signs and values to be comparable.
Common errors include counting a double bond once when the table separates its components, or forgetting a stoichiometric coefficient. Read the balanced equation and sketch reactant and product structures before calculating. A double bond contains one σ and one π bond if the table lists them separately, so follow its convention. Also keep amounts referenced to one mole of reaction. In the example, two H−Cl bonds form, so subtract 2·D(H−Cl). Finally, check that the sign matches the expected energy picture. Reversing the written reaction also reverses the sign of its estimated enthalpy change.
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