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Nusselt number compares convection with conduction across a characteristic length.
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Formula
Nu dimensionless; h in W/(m2·K); L in m; k in W/(m·K)
| Symbol | Meaning | Unit |
|---|---|---|
| Nusselt number | dimensionless | |
| Convective heat-transfer coefficient | W/(m2·K) | |
| Characteristic length for the correlation | m | |
| Fluid thermal conductivity | W/(m·K) |
\mathrm{Nu}=\frac{hL}{k}Nu also depends on geometry, Reynolds and Prandtl numbers and boundary conditions. The definition does not determine h without an applicable empirical or theoretical correlation. Use the same characteristic length as that correlation and properties at a suitable reference temperature.
Nu also depends on geometry, Reynolds and Prandtl numbers and boundary conditions. The definition does not determine h without an applicable empirical or theoretical correlation. Use the same characteristic length as that correlation and properties at a suitable reference temperature.
Nusselt number compares convection with conduction across a characteristic length.
Base equation for the target quantity
Preserve signs, boundary conditions and units when rearranging.
Work through the numerical example for “Nusselt number for convective heat transfer” and check its unit and magnitude.
For h=100 W/(m2·K), L=0.05 m and k=0.60 W/(m·K), Nu≈8.33.
Substituting a related quantity that shares the same symbol.
Use variable definitions and check: Nu dimensionless; h in W/(m2·K); L in m; k in W/(m·K).
Formula cluster
Nusselt number compares convection with conduction across a characteristic length.
For h=100 W/(m2·K), L=0.05 m and k=0.60 W/(m·K), Nu≈8.33.
Compare convection through dimensionless correlations.
Here is how to work through a typical Nusselt number for convective heat transfer (Nu = hL/k) task step by step:
Task
Work through the numerical example for “Nusselt number for convective heat transfer” and check its unit and magnitude.
Solution path
For h=100 W/(m2·K), L=0.05 m and k=0.60 W/(m·K), Nu≈8.33.
On the chosen length scale, dimensionless convection matches the fluid conduction scale. This is not a universal limiting case for every geometry; it follows from the definition. Nu is a dimensionless definition; obtain h from a correlation valid for the geometry and flow regime. Application: Compare convection through dimensionless correlations. The numerical example For h=100 W/(m2·K), L=0.05 m and k=0.60 W/(m·K), Nu≈8.33 anchors the idea in a concrete measurement case. The corresponding units are Nu dimensionless; h in W/(m2·K); L in m; k in W/(m·K). For h=100 W/(m2·K), L=0.05 m and k=0.60 W/(m·K), Nu≈8.33. This checks that the reference quantities are compatible.
Once a valid correlation gives Nu, rearrange to h=Nu·k/L. Fluid conductivity and characteristic length must match that correlation’s definitions. A wrong length directly biases the coefficient. Nu is a dimensionless definition; obtain h from a correlation valid for the geometry and flow regime. The corresponding units are Nu dimensionless; h in W/(m2·K); L in m; k in W/(m·K). For h=100 W/(m2·K), L=0.05 m and k=0.60 W/(m·K), Nu≈8.33. This checks that the reference quantities are compatible. Scope: Nu also depends on geometry, Reynolds and Prandtl numbers and boundary conditions. The definition does not determine h without an applicable empirical or theoretical correlation. Use the same characteristic length as that correlation and properties at a suitable reference temperature. A practical application is Compare convection through dimensionless correlations.
Forced-convection correlations often depend on Reynolds and Prandtl numbers; natural convection often uses Grashof or Rayleigh. Boundary conditions, geometry and flow development also matter. Extrapolating outside a correlation’s range is unreliable. Nu is a dimensionless definition; obtain h from a correlation valid for the geometry and flow regime. Scope: Nu also depends on geometry, Reynolds and Prandtl numbers and boundary conditions. The definition does not determine h without an applicable empirical or theoretical correlation. Use the same characteristic length as that correlation and properties at a suitable reference temperature. A practical application is Compare convection through dimensionless correlations.
Write the quantity and unit from the variable list next to every value: Nu dimensionless; h in W/(m2·K); L in m; k in W/(m·K). Substitute only after converting to a consistent unit system, and state sign or reference direction explicitly. The example For h=100 W/(m2·K), L=0.05 m and k=0.60 W/(m·K), Nu≈8.33. is a calculation check: result, unit and order of magnitude must fit the described situation. Round after intermediate calculations so small contributions are not lost prematurely. Nu is a dimensionless definition; obtain h from a correlation valid for the geometry and flow regime.
The background states this starting condition: Nu also depends on geometry, Reynolds and Prandtl numbers and boundary conditions. The definition does not determine h. That limits when the result is a valid model prediction. Compare the problem’s boundary conditions with this assumption before substituting values; real components, material properties or loads can introduce additional effects. The cited reference supports the relation used here but does not remove the need to check whether the specific case fits the model. Nu is a dimensionless definition; obtain h from a correlation valid for the geometry and flow regime.
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Curated exam set for "Nusselt number for convective heat transfer":
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Which formula describes Nusselt number for convective heat transfer?
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How do you rearrange Nusselt number for convective heat transfer for Base equation for the target quantity?
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Which common mistake happens with Nusselt number for convective heat transfer?
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