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Belt power equals belt speed times the difference between tight-side and slack-side tensions.
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Formula
P in W; F in N; v in m/s
| Symbol | Meaning | Unit |
|---|---|---|
| Transmitted mechanical power | W | |
| Tight-side tension | N | |
| Slack-side tension | N | |
| Belt speed | m/s |
P=(F_1-F_2)vThe tension difference is the net tangential force; multiplying by common belt speed gives power. It assumes steady operation and no local slip. Allowable belt rating also depends on pretension, wrap angle, material, temperature and service life.
The tension difference is the net tangential force; multiplying by common belt speed gives power. It assumes steady operation and no local slip. Allowable belt rating also depends on pretension, wrap angle, material, temperature and service life.
Belt power equals belt speed times the difference between tight-side and slack-side tensions.
Base equation for the target quantity
Preserve signs, boundary conditions and units when rearranging.
Work through the numerical example for “Power transmitted by a belt” and check its unit and magnitude.
For F1=900 N, F2=300 N and v=12 m/s, P=7.2 kW.
Substituting a related quantity that shares the same symbol.
Use variable definitions and check: P in W; F in N; v in m/s.
Formula cluster
Belt power equals belt speed times the difference between tight-side and slack-side tensions.
For F1=900 N, F2=300 N and v=12 m/s, P=7.2 kW.
Calculate power transmitted by a running belt from span tensions.
Here is how to work through a typical Power transmitted by a belt (P = (F1−F2)v) task step by step:
Task
Work through the numerical example for “Power transmitted by a belt” and check its unit and magnitude.
Solution path
For F1=900 N, F2=300 N and v=12 m/s, P=7.2 kW.
The two span tensions act in opposite rotational directions. Their difference is the net tangential force that creates torque. Their sum mainly affects bearing load and pretension, not transmitted power. Assume steady belt speed and no slip at pulley contact. Application: Calculate power transmitted by a running belt from span tensions. The numerical example For F1=900 N, F2=300 N and v=12 m/s, P=7.2 kW anchors the idea in a concrete measurement case. The corresponding units are P in W; F in N; v in m/s. For F1=900 N, F2=300 N and v=12 m/s, P=7.2 kW. This checks that the reference quantities are compatible.
Transmitted torque is (F1−F2)r. Using angular speed ω and belt speed v=rω gives P=Tω=(F1−F2)v, consistent with force times velocity. Assume steady belt speed and no slip at pulley contact. The corresponding units are P in W; F in N; v in m/s. For F1=900 N, F2=300 N and v=12 m/s, P=7.2 kW. This checks that the reference quantities are compatible. Scope: The tension difference is the net tangential force; multiplying by common belt speed gives power. It assumes steady operation and no local slip. Allowable belt rating also depends on pretension, wrap angle, material, temperature and service life. A practical application is Calculate power transmitted by a running belt from span tensions.
With slip, belt and pulley-rim speeds differ. The simple equation using one shared v only approximates actual power transfer. Temperature, friction coefficient and wear also limit available tension difference. Assume steady belt speed and no slip at pulley contact. Scope: The tension difference is the net tangential force; multiplying by common belt speed gives power. It assumes steady operation and no local slip. Allowable belt rating also depends on pretension, wrap angle, material, temperature and service life. A practical application is Calculate power transmitted by a running belt from span tensions.
Write the quantity and unit from the variable list next to every value: P in W; F in N; v in m/s. Substitute only after converting to a consistent unit system, and state sign or reference direction explicitly. The example For F1=900 N, F2=300 N and v=12 m/s, P=7.2 kW. is a calculation check: result, unit and order of magnitude must fit the described situation. Round after intermediate calculations so small contributions are not lost prematurely. Assume steady belt speed and no slip at pulley contact.
The background states this starting condition: The tension difference is the net tangential force; multiplying by common belt speed gives power. It assumes steady. That limits when the result is a valid model prediction. Compare the problem’s boundary conditions with this assumption before substituting values; real components, material properties or loads can introduce additional effects. The cited reference supports the relation used here but does not remove the need to check whether the specific case fits the model. Assume steady belt speed and no slip at pulley contact.
Quanta exam set
Curated exam set for "Power transmitted by a belt":
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Which formula describes Power transmitted by a belt?
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How do you rearrange Power transmitted by a belt for Base equation for the target quantity?
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Which common mistake happens with Power transmitted by a belt?
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