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A linear network viewed at two terminals can be replaced by an ideal voltage source in series with a resistance.
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Formula
U in V; I in A; R in Ω
| Symbol | Meaning | Unit |
|---|---|---|
| Open-circuit terminal voltage | V | |
| Equivalent internal resistance | Ω | |
| Short-circuit current at the same terminals | A |
U_{Th}=U_{oc},\quad R_{Th}=\frac{U_{oc}}{I_{sc}}The equivalent reproduces the terminal behavior of a linear network for attached loads. UTh is the open-circuit voltage; RTh can be found with independent sources deactivated or from Uoc/Isc. Dependent sources remain active and need separate treatment. Nonlinear elements generally have no global Thevenin pair.
The equivalent reproduces the terminal behavior of a linear network for attached loads. UTh is the open-circuit voltage; RTh can be found with independent sources deactivated or from Uoc/Isc. Dependent sources remain active and need separate treatment. Nonlinear elements generally have no global Thevenin pair.
A linear network viewed at two terminals can be replaced by an ideal voltage source in series with a resistance.
Base equation for the target quantity
Preserve signs, boundary conditions and units when rearranging.
Work through the numerical example for “Thevenin equivalent of a linear two-terminal network” and check its unit and magnitude.
A network with Uoc=12 V and Isc=2 A has RTh=6 Ω; a 6 Ω load receives 6 V.
Substituting a related quantity that shares the same symbol.
Use variable definitions and check: U in V; I in A; R in Ω.
Formula cluster
A linear network viewed at two terminals can be replaced by an ideal voltage source in series with a resistance.
A network with Uoc=12 V and Isc=2 A has RTh=6 Ω; a 6 Ω load receives 6 V.
Reduce a complex linear circuit when analyzing one load.
Here is how to work through a typical Thevenin equivalent of a linear two-terminal network (UTh = Uoc; RTh = Uoc/Isc) task step by step:
Task
Work through the numerical example for “Thevenin equivalent of a linear two-terminal network” and check its unit and magnitude.
Solution path
A network with Uoc=12 V and Isc=2 A has RTh=6 Ω; a 6 Ω load receives 6 V.
Remove the load at the chosen terminals and calculate the open-circuit voltage with consistent polarity. That voltage is UTh. Keep dependent sources active; a test source may be needed to find resistance. Keep terminals and source convention fixed; retain dependent sources while finding resistance. Application: Reduce a complex linear circuit when analyzing one load. The numerical example A network with Uoc=12 V and Isc=2 A has RTh=6 Ω; a 6 Ω load receives 6 V anchors the idea in a concrete measurement case.
For a linear network with independent sources, short ideal voltage sources and open ideal current sources, then look into the terminals. Alternatively use RTh=Uoc/Isc when both are measured consistently. Do not deactivate dependent sources. Keep terminals and source convention fixed; retain dependent sources while finding resistance. The corresponding units are U in V; I in A; R in Ω. A network with Uoc=12 V and Isc=2 A has RTh=6 Ω; a 6 Ω load receives 6 V. This checks that the reference quantities are compatible.
A correct Thevenin model reproduces terminal voltage-current behavior for any attached load while the surrounding network remains linear. It does not preserve internal voltages or powers. Time-varying or nonlinear sources require an adapted model. Keep terminals and source convention fixed; retain dependent sources while finding resistance. Scope: The equivalent reproduces the terminal behavior of a linear network for attached loads. UTh is the open-circuit voltage; RTh can be found with independent sources deactivated or from Uoc/Isc. Dependent sources remain active and need separate treatment. Nonlinear elements generally have no global Thevenin pair. A practical application is Reduce a complex linear circuit when analyzing one load.
Write the quantity and unit from the variable list next to every value: U in V; I in A; R in Ω. Substitute only after converting to a consistent unit system, and state sign or reference direction explicitly. The example A network with Uoc=12 V and Isc=2 A has RTh=6 Ω; a 6 Ω load receives 6 V. is a calculation check: result, unit and order of magnitude must fit the described situation. Round after intermediate calculations so small contributions are not lost prematurely. Keep terminals and source convention fixed; retain dependent sources while finding resistance.
The background states this starting condition: The equivalent reproduces the terminal behavior of a linear network for attached loads. UTh is the open-circuit voltage;. That limits when the result is a valid model prediction. Compare the problem’s boundary conditions with this assumption before substituting values; real components, material properties or loads can introduce additional effects. The cited reference supports the relation used here but does not remove the need to check whether the specific case fits the model. Keep terminals and source convention fixed; retain dependent sources while finding resistance.
Quanta exam set
Curated exam set for "Thevenin equivalent of a linear two-terminal network":
Question (front)
Which formula describes Thevenin equivalent of a linear two-terminal network?
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How do you rearrange Thevenin equivalent of a linear two-terminal network for Base equation for the target quantity?
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Which common mistake happens with Thevenin equivalent of a linear two-terminal network?
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