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The chromatographic selectivity factor compares the retention of two analytes after correcting for mobile-phase dead time.
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Formula
α and k dimensionless · retention times in the same time unit
| Symbol | Meaning | Unit |
|---|---|---|
| selectivity factor | dimensionless | |
| retention factors of peaks 1 and 2 | dimensionless | |
| retention times | min or s | |
| mobile-phase dead time | min or s |
\alpha=\frac{k_2}{k_1}=\frac{t_{R,2}-t_M}{t_{R,1}-t_M}Label peak 2 as the more retained analyte so α≥1. Measure retention times and dead time consistently under identical conditions. Selectivity alone does not determine peak resolution, which also depends on efficiency and peak width.
Label peak 2 as the more retained analyte so α≥1. Measure retention times and dead time consistently under identical conditions. Selectivity alone does not determine peak resolution, which also depends on efficiency and peak width.
The chromatographic selectivity factor compares the retention of two analytes after correcting for mobile-phase dead time.
Rearrange for a target quantity
The rearrangement keeps the same model assumptions as the original relation.
Calculate Chromatographic Selectivity Factor from the stated example data and explain the check.
For tM=1.0 min, tR1=4.0 min and tR2=5.5 min, k1=3.0, k2=4.5 and α=1.50.
Check: α>1 because peak 2 is more retained.
Applying Chromatographic Selectivity Factor with inconsistent reference states or without checking the stated model assumptions.
Keep the standard state, units, and model assumptions explicit; compare them with the measured system before interpreting the result.
Formula cluster
Chromatographic Selectivity Factor answers a distinct subquestion. Linked relations complement it when their additional assumptions are met.
For tM=1.0 min, tR1=4.0 min and tR2=5.5 min, k1=3.0, k2=4.5 and α=1.50. Check: α>1 because peak 2 is more retained.
Compare chromatographic conditions for their ability to distinguish analytes.
Here is how to work through a typical Chromatographic Selectivity Factor (α = k₂/k₁) task step by step:
Task
Calculate Chromatographic Selectivity Factor from the stated example data and explain the check.
Solution path
For tM=1.0 min, tR1=4.0 min and tR2=5.5 min, k1=3.0, k2=4.5 and α=1.50.
Check: α>1 because peak 2 is more retained.
The chromatographic selectivity factor compares the retention of two analytes after correcting for mobile-phase dead time. The relation is useful for Compare chromatographic conditions for their ability to distinguish analytes.. For tM=1.0 min, tR1=4.0 min and tR2=5.5 min, k1=3.0, k2=4.5 and α=1.50. Check: α>1 because peak 2 is more retained. The final check tests a balance, direction or magnitude relevant to this formula. First map each quantity to the actual experiment, then substitute values. The result describes the modelled relationship; it does not automatically establish every mechanism in the real sample.
The symbols mean: α: selectivity factor (dimensionless); k1,k2: retention factors of peaks 1 and 2 (dimensionless); tR1,tR2: retention times (min or s); tM: mobile-phase dead time (min or s). Follow α and k dimensionless · retention times in the same time unit. Concentrations, activities, volumes and times must use compatible scales. A logarithm needs a dimensionless argument, and a balance must include all contributing species. State temperature and standard state whenever they are part of the definition; otherwise the result may refer to a different chemical condition. An amount is not a mass without molar mass, and activity is not an unnormalised concentration. Say whether inputs were measured or taken from a reference.
Label peak 2 as the more retained analyte so α≥1. Measure retention times and dead time consistently under identical conditions. Selectivity alone does not determine peak resolution, which also depends on efficiency and peak width. Check this assumption for the actual sample, temperature and phase. Nonideality, mass transport or side reactions can make a precise calculation systematically wrong. Compare the balanced reaction and the activity or concentration scale with the model, then state the assumption that most affects the result. Near model boundaries, check activities and phase state rather than extending a dilute-solution approximation. Different conditions require a fresh model check.
Recalculate the example: For tM=1.0 min, tR1=4.0 min and tR2=5.5 min, k1=3.0, k2=4.5 and α=1.50. Check: α>1 because peak 2 is more retained. Check α and k dimensionless · retention times in the same time unit and substitute the value back into the relation. Also ask whether its sign, balance or magnitude is chemically plausible. If a check fails, inspect units, coefficients and reference values before blaming rounding. Substitution checks the algebra; comparing assumptions with the experiment checks whether the model is appropriate.
Chromatographic Selectivity Factor is related to Chromatographic Retention Factor, Chromatographic Resolution, Linear Calibration Line, Van Deemter Equation, but answers a distinct question: Compare chromatographic conditions for their ability to distinguish analytes.. Do not confuse it with a relation for a neighboring quantity or a different standard state. Name the target quantity and sample conditions first, then choose the equation containing that quantity. Similar-looking equations may use different stoichiometric bases or validity ranges. The linked entries may supply inputs for another step, but they do not replace this distinction. This keeps the interpretation auditable.
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Curated exam set for "Chromatographic Selectivity Factor":
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Which formula describes Chromatographic Selectivity Factor?
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How do you rearrange Chromatographic Selectivity Factor for Rearrange for a target quantity?
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Which common mistake happens with Chromatographic Selectivity Factor?
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