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Implicit differentiation finds the local slope of a curve defined by F(x,y)=0 without first solving explicitly for y.
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Formula
y′ has units of y divided by x; Fx and Fy carry the corresponding derivative units.
| Symbol | Meaning | Unit |
|---|---|---|
| differentiable function defining F(x,y)=0 | dependent on F | |
| coordinates of a point on the curve | respective coordinate unit | |
| partial derivatives with respect to x and y | unit of F per corresponding coordinate unit |
F(x,y)=0\;\Longrightarrow\; y'=-\frac{F_x}{F_y}Along a solution curve y=y(x), F(x,y(x)) remains zero. The chain rule gives Fx+Fy y′=0; when Fy≠0 this yields the slope formula. It describes a local graph y(x), not necessarily the entire curve; when Fy=0, a vertical tangent may occur.
Along a solution curve y=y(x), F(x,y(x)) remains zero. The chain rule gives Fx+Fy y′=0; when Fy≠0 this yields the slope formula. It describes a local graph y(x), not necessarily the entire curve; when Fy=0, a vertical tangent may occur.
The subject assumption is translated into a measurable relationship: Along a solution curve y=y(x), F(x,y(x)) remains zero. The chain rule gives Fx+Fy y′=0; when Fy≠0 this yields the slope formula. It describes a local graph y(x), not necessarily the entire curve; when Fy=0, a vertical tangent may occur.
Local slope
Valid locally as y(x) when Fy is nonzero.
Calculate and justify the value in the example: For x2+y2=25, Fx=2x and Fy=2y, so y′=−x/y. At (3,4), the slope is −3/4. Check: 2·3+2·4·(−3/4)=6−6=0, so the tangent satisfies the differentiated equation.
For x2+y2=25, Fx=2x and Fy=2y, so y′=−x/y.
At (3,4), the slope is −3/4.
Check: 2·3+2·4·(−3/4)=6−6=0, so the tangent satisfies the differentiated equation.
Using a variable with the wrong meaning or unit, thereby exceeding the model’s domain.
Match each variable to its definition, make units consistent and state the assumption being used.
Formula cluster
This page places Implicit Differentiation in Find tangents to implicit curves and analyze constraints in calculus and optimization.
For x2+y2=25, Fx=2x and Fy=2y, so y′=−x/y. At (3,4), the slope is −3/4. Check: 2·3+2·4·(−3/4)=6−6=0, so the tangent satisfies the differentiated equation.
Find tangents to implicit curves and analyze constraints in calculus and optimization.
Here is how to work through a typical Implicit Differentiation (y′ = −Fx/Fy bei Fy ≠ 0) task step by step:
Task
Calculate and justify the value in the example: For x2+y2=25, Fx=2x and Fy=2y, so y′=−x/y. At (3,4), the slope is −3/4. Check: 2·3+2·4·(−3/4)=6−6=0, so the tangent satisfies the differentiated equation.
Solution path
For x2+y2=25, Fx=2x and Fy=2y, so y′=−x/y.
At (3,4), the slope is −3/4.
Check: 2·3+2·4·(−3/4)=6−6=0, so the tangent satisfies the differentiated equation.
The relation y′ = −Fx/Fy bei Fy ≠ 0 connects quantities in Differential calculus. It answers this practical question: Find tangents to implicit curves and analyze constraints in calculus and optimization. Read every symbol with its definition in the variable list; the same letter can mean something different in another topic. The equation alone does not specify how a quantity was measured or which model assumptions apply. First list the inputs, the unknown and their units. Then check whether the relationship described by the formula matches the situation. This prevents a numerically plausible value from being inserted into the wrong physical, geometric or calculus setting.
The derivation starts from this subject-specific idea: differentiate F(x,y(x))=0 with respect to x. The chain rule gives Fx+Fy y′=0; then solve for y′. This accounts for dependence y(x) without first isolating y explicitly. It leads to y′ = −Fx/Fy bei Fy ≠ 0. In a solution, first separate the definitions of the quantities from the model assumptions; then perform the required geometric, algebraic or physical step. This makes clear why the formula holds and which condition matters. After rearranging, check that the unknown is isolated, the units are consistent and the original domain of validity has been preserved.
The worked example uses concrete, compatible quantities: For x2+y2=25, Fx=2x and Fy=2y, so y′=−x/y. At (3,4), the slope is −3/4. Check: 2·3+2·4·(−3/4)=6−6=0, so the tangent satisfies the differentiated equation. A number is meaningful only when its units and reference points are carried through. Convert inputs to a common unit before substituting them into the stated relation. The check in the example tests an independent consequence, rather than repeating the same arithmetic. Changing an input should also produce the expected trend. If the result conflicts with that trend, check conversions, signs and the mapping between variables before reporting extra decimal places. This makes the calculation auditable instead of merely calculator-generated.
Before applying the formula, check this limit: the displayed slope form requires Fy to be nonzero. A circle has no finite y(x) slope at its side points; the tangent is vertical there, so another local description is needed. This is not a formal footnote; it determines whether the relationship describes the problem at all. Compare the given information with the variable definitions and state any idealizations explicitly. An order-of-magnitude estimate or limiting case can then test plausibility. If the condition fails, use a broader model or restrict the claim to the valid domain; adding decimal places cannot repair a wrong model choice.
A common error is to substitute visible numbers without checking what the variables mean. In this case, pay particular attention to: y′ has units of y divided by x; Fx and Fy carry the corresponding derivative units. A geometrically or algebraically correct result is still wrong if, for example, a perpendicular height is replaced by a slanted side, a magnitude by a directed quantity, or an approximation by an exact equality. Use a sketch or sign convention when the relationship needs one. As a final check, substitute the result into the original relation and inspect dimensions, a limiting case and the expected trend.
Quanta exam set
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Which formula describes Implicit Differentiation?
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How do you rearrange Implicit Differentiation for Local slope?
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Which common mistake happens with Implicit Differentiation?
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