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The Shannon-Hartley limit gives the maximum reliably transmitted data rate of a band-limited AWGN channel.
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Formula
C in bit/s; B in Hz; S/N is a dimensionless linear power ratio, not dB
| Symbol | Meaning | Unit |
|---|---|---|
| Theoretical channel capacity | bit/s | |
| Channel bandwidth | Hz | |
| Received signal-to-noise power ratio | dimensionless |
C=B\log_2(1+S/N)The formula applies to a band-limited additive white Gaussian noise (AWGN) channel and a linear SNR. It is an asymptotic limit for reliable communication with suitable coding, not the rate every practical system achieves. If SNR is given in decibels, first calculate SNRlin=10^(SNRdB/10). Bandwidth raises C linearly, whereas increasing SNR has only a logarithmic effect.
The formula applies to a band-limited additive white Gaussian noise (AWGN) channel and a linear SNR. It is an asymptotic limit for reliable communication with suitable coding, not the rate every practical system achieves. If SNR is given in decibels, first calculate SNRlin=10^(SNRdB/10). Bandwidth raises C linearly, whereas increasing SNR has only a logarithmic effect.
The Shannon-Hartley limit gives the maximum reliably transmitted data rate of a band-limited AWGN channel.
SNR from capacity
SNR in the equation is linear, not in dB.
Use the example for Shannon-Hartley channel capacity to explain which inputs determine the requested output.
The example connects concrete inputs to its result.
The Shannon-Hartley limit gives the maximum reliably transmitted data rate of a band-limited AWGN channel.
The relation applies only under its stated assumptions.
Applying the relation to a different case without checking its stated assumptions.
Check the validity range before substituting values: The formula applies to a band-limited additive white Gaussian noise (AWGN) channel and a linear SNR. It is an asymptotic limit for reliable communication with suitable coding, not the rate.
Formula cluster
The Shannon-Hartley limit gives the maximum reliably transmitted data rate of a band-limited AWGN channel.
For B=1 MHz and SNR=15 (about 11.76 dB), C=106·log2(16)=4 Mbit/s as a theoretical limit.
Interpret theoretical data rates and spectral efficiency of communication channels.
Here is how to work through a typical Shannon-Hartley channel capacity (C = B·log₂(1+SNR)) task step by step:
Task
Use the example for Shannon-Hartley channel capacity to explain which inputs determine the requested output.
Solution path
The example connects concrete inputs to its result.
The Shannon-Hartley limit gives the maximum reliably transmitted data rate of a band-limited AWGN channel.
The relation applies only under its stated assumptions.
Channel capacity is the theoretical rate below which suitable coding can make communication arbitrarily reliable. It does not promise that a particular modem reaches that rate. For an AWGN channel, the Shannon-Hartley limit depends on bandwidth B and linear SNR. Real systems need margin and resources for protocols, synchronization and error correction. The bound assumes a band-limited AWGN channel and suitable coding. Practical protocols fall below it because of finite block length, hardware and overhead; interpret C as an upper limit. It is not a guaranteed payload rate for an arbitrary Wi-Fi link or modem. Also check the assumed noise model.
The logarithm takes the power ratio itself, not its decibel representation. At SNRdB=10 dB, SNRlin=10^(10/10)=10; treating a dB value as a ratio gives a mis-scaled result. Convert first using 10^(SNRdB/10). Voltage ratios use a different decibel definition and require extra care. The bound assumes a band-limited AWGN channel and suitable coding. Practical protocols fall below it because of finite block length, hardware and overhead; interpret C as an upper limit. It is not a guaranteed payload rate for an arbitrary Wi-Fi link or modem. Also check the assumed noise model.
Substitute B=1 MHz and SNR=15. Since 1+15=16 and log216=4, C=106·4=4·106 bit/s, or 4 Mbit/s. Check the unit: hertz times a dimensionless spectral-efficiency factor gives bit/s. The value is idealized; a practical finite-delay code does not reach it exactly. The bound assumes a band-limited AWGN channel and suitable coding. Practical protocols fall below it because of finite block length, hardware and overhead; interpret C as an upper limit. It is not a guaranteed payload rate for an arbitrary Wi-Fi link or modem. Also check the assumed noise model.
At fixed linear SNR, C is proportional to B, so doubling bandwidth doubles the formula’s capacity. In real channels, extra bandwidth can also admit more noise, so SNR may not stay fixed. The simple scaling holds only when S/N is kept fixed for the bandwidth considered and the AWGN model applies. The bound assumes a band-limited AWGN channel and suitable coding. Practical protocols fall below it because of finite block length, hardware and overhead; interpret C as an upper limit. It is not a guaranteed payload rate for an arbitrary Wi-Fi link or modem. Also check the assumed noise model.
Information theory says rates below capacity can be made arbitrarily reliable with suitable coding and sufficiently long blocks. This is an existence limit, not a recipe for a short code. Approaching it usually costs computation, latency and complexity. Account for bandwidth limits, channel variation and implementation losses before planning a real data rate. The bound assumes a band-limited AWGN channel and suitable coding. Practical protocols fall below it because of finite block length, hardware and overhead; interpret C as an upper limit. It is not a guaranteed payload rate for an arbitrary Wi-Fi link or modem. Also check the assumed noise model.
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Which formula describes Shannon-Hartley channel capacity?
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How do you rearrange Shannon-Hartley channel capacity for SNR from capacity?
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Which common mistake happens with Shannon-Hartley channel capacity?
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