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Fluid drag can scale linearly with relative speed for creeping flow around a sphere or quadratically for many bluff bodies at higher Reynolds numbers; a sphere’s Stokes-regime terminal speed follows from balancing effective weight against drag.
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Formula
Force in N; terminal speed in m/s; η in Pa·s; r and d in m; ρs and ρf in kg/m3; g in m/s2; A in m2; CD and Reynolds number are dimensionless.
| Symbol | Meaning | Unit |
|---|---|---|
| Drag force opposing relative motion | N | |
| Dynamic viscosity | Pa·s | |
| Sphere radius | m | |
| vrel | Relative speed | m/s |
| Fluid density | kg/m3 | |
| Sphere density | kg/m3 | |
| Gravitational acceleration | m/s2 | |
| Terminal settling speed when ρs>ρf | m/s | |
| Drag coefficient | dimensionless | |
| Reference area | m2 | |
| Particle Reynolds number ρf d|vrel|/η | dimensionless |
F_D=6\pi\eta r|v_{rel}|,\quad v_t=\frac{2r^2(\rho_s-\rho_f)g}{9\eta}\ (Re_p\ll1);\quad F_D=\frac12\rho_f C_DA v_{rel}^2\ (Re_p\gg1)Original schematic by Quanta
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Stokes’ law F=6πηrv applies to a rigid sphere in steady creeping flow with particle Reynolds number much less than one. For a sinking sphere, terminal speed follows by balancing weight minus buoyancy with drag: (4/3)πr3(ρs−ρf)g=6πηrvt, giving vt=2r2(ρs−ρf)g/(9η) when ρs>ρf. The quadratic model FD=½ρC_DAv2 is common for bluff bodies when inertial effects dominate; CD depends on shape and flow regime. Neither formula is a universal drag law, and transitional flow can require empirical correlations. Use fluid-relative speed and include the force direction opposite that velocity.
Stokes’ law F=6πηrv applies to a rigid sphere in steady creeping flow with particle Reynolds number much less than one. For a sinking sphere, terminal speed follows by balancing weight minus buoyancy with drag: (4/3)πr3(ρs−ρf)g=6πηrvt, giving vt=2r2(ρs−ρf)g/(9η) when ρs>ρf. The quadratic model FD=½ρC_DAv2 is common for bluff bodies when inertial effects dominate; CD depends on shape and flow regime. Neither formula is a universal drag law, and transitional flow can require empirical correlations. Use fluid-relative speed and include the force direction opposite that velocity.
Fluid drag can scale linearly with relative speed for creeping flow around a sphere or quadratically for many bluff bodies at higher Reynolds numbers; a sphere’s Stokes-regime terminal speed follows from balancing effective weight against drag.
Particle Reynolds number for model selection
For a sphere of diameter 2r, Stokes applies at Re_p≪1; quadratic drag is an approximation in an inertia-dominated regime, not at the transition.
Terminal settling speed at low Reynolds number
Spherical body, ρs>ρf, weight minus buoyancy balances Stokes drag, and Rep≪1.
A sphere with r=1.0 μm moves at 0.010 m/s in a fluid (η=1.0×10−3 Pa·s, ρ=1000 kg/m3). Check Rep and calculate Stokes drag.
Rep=ρ(2r)v/η=0.020≪1, so Stokes flow is plausible: FD=6πηrv≈1.88×10−10 N.
A body in air has ρ=1.2 kg/m3, CD=0.47, A=0.010 m2 and v=20 m/s. Calculate quadratic drag.
FD=½ρCDAv2=½·1.2·0.47·0.010·202≈1.13 N.
A sphere with ρs=2500 kg/m3 and r=50 μm sinks in a fluid with ρf=1000 kg/m3 and η=0.10 Pa·s. Calculate vt and check Re_p.
From (4/3)πr3(ρs−ρf)g=6πηrv_t, vt=2r2(ρs−ρf)g/(9η)=8.18×10−5 m/s.
Re_p=ρf(2r)vt/η≈8.2×10−5≪1, so Stokes is self-consistent.
Ignoring units or assumptions stated for the formula: Force in N; terminal speed in m/s; η in Pa·s; r and d in m; ρs and ρf in kg/m3; g in m/s2; A in m2; CD and Reynolds number are dimensionless.
Convert units before substitution and verify the validity range; round only at the end.
Formula cluster
Related relations: newton-zweites-gesetz, gewichtskraft, reibungskraft.
For r=1.0 μm and v=0.010 m/s in a fluid with η=1.0×10−3 Pa·s and ρf=1000 kg/m3, Rep=0.020≪1 and drag is about 1.88×10−10 N. Also, for r=50 μm, ρs=2500 kg/m3, ρf=1000 kg/m3 and η=0.10 Pa·s, vt=2r2(ρs−ρf)g/(9η)≈8.18×10−5 m/s. Check: Rep≈8.2×10−5≪1, so the Stokes assumption is satisfied.
Choose a drag model for particle settling, falling objects and fluid-flow estimates.
Here is how to work through a typical Stokes Drag, Terminal Settling Speed and Quadratic Drag (FD=6πηr|vrel|; vt=2r²(ρs−ρf)g/(9η) (Re≪1); FD=½ρfCDAvrel² (Re≫1)) task step by step:
Task
A sphere with r=1.0 μm moves at 0.010 m/s in a fluid (η=1.0×10−3 Pa·s, ρ=1000 kg/m3). Check Rep and calculate Stokes drag.
Solution path
Rep=ρ(2r)v/η=0.020≪1, so Stokes flow is plausible: FD=6πηrv≈1.88×10−10 N.
Task
A body in air has ρ=1.2 kg/m3, CD=0.47, A=0.010 m2 and v=20 m/s. Calculate quadratic drag.
Solution path
FD=½ρCDAv2=½·1.2·0.47·0.010·202≈1.13 N.
Task
A sphere with ρs=2500 kg/m3 and r=50 μm sinks in a fluid with ρf=1000 kg/m3 and η=0.10 Pa·s. Calculate vt and check Re_p.
Solution path
From (4/3)πr3(ρs−ρf)g=6πηrv_t, vt=2r2(ρs−ρf)g/(9η)=8.18×10−5 m/s.
Re_p=ρf(2r)vt/η≈8.2×10−5≪1, so Stokes is self-consistent.
The relation for Stokes Drag, Terminal Settling Speed and Quadratic Drag connects measurable quantities and shows which variables determine the result. Fluid drag can scale linearly with relative speed for creeping flow around a sphere or quadratically for many bluff bodies at higher Reynolds numbers; a sphere’s Stokes-regime terminal speed follows from balancing effective weight against drag. First define the state and reference used. The equation is more than a shortcut: its proportionalities let you predict changes without numerical calculation. Ask whether doubling an input doubles the result, or whether an angle, area or squared distance changes that dependence. This qualitative check helps catch an incorrect setup early and gives a physical interpretation to the number obtained. It also clarifies which measurement needs the greatest care.
For r=1.0 μm and v=0.010 m/s in a fluid with η=1.0×10−3 Pa·s and ρf=1000 kg/m3, Rep=0.020≪1 and drag is about 1.88×10−10 N. Also, for r=50 μm, ρs=2500 kg/m3, ρf=1000 kg/m3 and η=0.10 Pa·s, vt=2r2(ρs−ρf)g/(9η)≈8.18×10−5 m/s. Check: Rep≈8.2×10−5≪1, so the Stokes assumption is satisfied. A reliable calculation lists known quantities with units, rearranges for the unknown, and rounds only at the end. Compare the output unit and magnitude with the described process; the equation alone cannot tell whether the input data are sensible. If a result seems surprising, check signs, unit conversions and angle definitions first. A limiting-case check helps too: imagine setting a parameter to zero or doubling it, then ask whether the result responds as the model predicts. In an experiment, record measurements separately from assumptions so discrepancies can be traced to arithmetic or idealisation.
Stokes drag for a rigid sphere assumes steady creeping flow with Rep≪1. The settling formula additionally follows from weight minus buoyancy equalling drag and requires ρs>ρf. By contrast, the quadratic model suits many bluff bodies when inertial effects dominate; its CD depends on shape and Reynolds number. There is no sharp universal switch between the regimes. Check Rep and geometry before choosing a drag model. Both equations give the force magnitude; the vector force points opposite the relative velocity. Settling speed must also account for buoyancy.
Write the units beside every measured value and convert them before substitution. Then check that both sides of the relation have matching dimensions; for example, a velocity must have length per time, whereas energy must be in joules. For r=1.0 μm and v=0.010 m/s in a fluid with η=1.0×10−3 Pa·s and ρf=1000 kg/m3, Rep=0.020≪1 and drag is about 1.88×10−10 N. Also, for r=50 μm, ρs=2500 kg/m3, ρf=1000 kg/m3 and η=0.10 Pa·s, vt=2r2(ρs−ρf)g/(9η)≈8.18×10−5 m/s. Check: Rep≈8.2×10−5≪1, so the Stokes assumption is satisfied. gives a concrete scale check: compare the result with the physical situation and ask whether its magnitude is plausible. Avoid rounding intermediate values too early, because small rounding errors can grow through powers, roots or very small quantities. Correct dimensions do not prove a calculation, but they rule out many wrong rearrangements and unit mistakes.
Choose a drag model for particle settling, falling objects and fluid-flow estimates. In a problem this relation often supplies only part of the description: another equation may add a missing measurement, a conservation balance or a boundary condition. First define the system and list the quantities known for it. Then use each formula only under its own assumptions; the same symbol can play different roles in different models. Write the combined reasoning in clear steps. This makes it possible to see which conclusion comes from Stokes Drag, Terminal Settling Speed and Quadratic Drag and what information the additional relation contributes.
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Curated exam set for "Stokes Drag, Terminal Settling Speed and Quadratic Drag":
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Which formula describes Stokes Drag, Terminal Settling Speed and Quadratic Drag?
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How do you rearrange Stokes Drag, Terminal Settling Speed and Quadratic Drag for Particle Reynolds number for model selection?
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Which common mistake happens with Stokes Drag, Terminal Settling Speed and Quadratic Drag?
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